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Kobotan [32]
3 years ago
15

Patty has just completed her second semester in college. She earned a grade of B in her 4​-hour topology ​course, a grade of D i

n her 11​-hour government ​course, a grade of D in her 2​-hour biology ​course, and a grade of D in her 3​-hour studio art course. Assuming that A equals 4​ points, B equals 3​ points, C equals 2​points, D equals 1​ point, and F is worth no​ points, determine Patty​'s ​grade-point average for the semester.
Mathematics
1 answer:
umka21 [38]3 years ago
8 0

Answer: 1.4

Step-by-step explanation:

To calculate the grade point average you have to sum all the points of each course multiplying the hours and then diveded by the total number of hours she did.

She earned a grade B in her 4 hour topology course, so she has 3*4 points.

In her 11 hour gouvernment course, she earned a grade D, so she has 1*11 points. In the 2 hour biology course she earned a grade D, so she has 1*2 points and in her 3 hours studio art course she had also a grade D, so she has 1*3 points

She has done 3+2+11+4 hours of subjects=20.

The total average is (3*4+1*11+1*2+1*3)/20=28/20=1.4

You might be interested in
Explanation of Baye's theorem.
ELEN [110]

I will be including both an basic explanation of what it is and its proof.

I'm guessing you are either learning about conditional probability at school or preparing for competitions.

Baye's theorem states:

P(A|B)=\frac{P(B|A)P(A)}{P(B)}

That is the theorem itself and it means that the probability that event A happens given B is true equals the probability event B happens given A is true times the probability event A happens divided by the probability B happens.

That was the basic of the theorem and the proof of this is basically just testing how well you understand what conditional probability is.

P(A|B)=\frac{P(AintersectB)}{P(B)}

P(B|A)=\frac{P(BintersectA)}{P(A)}

Now we know that the probably that A and B both happens is the same as the probably that B and A both happens.

Therefore P(A|B) can be seen as P(B|A) multiplied by P(A) and then divided by P(B) which gives the right hand side of the first equation. And this is basically the theorem.

P(A|B)=\frac{P(B|A)P(A)}{P(B)}

**Note P(B) have to be not equal to 0 because having a 0 in the denominator would make this equation undefined.

If you have any questions or need further explanations please ask me in the comments of the answer, I hope this helped!

6 0
3 years ago
Please help, I’m struggling
Naddika [18.5K]

Answer:

49.5 mi

Step-by-step explanation:

Area of a triangle is   A = (height) X (base) / 2

So if you plug in the numbers you get:

806.9 = (32.6) X (base) / 2

1613.8 = (32.6) X (base)

1613.8 / 32.6 = base

base =  49.5 mi

8 0
3 years ago
You bike 1 mile the first day of your​ training, 1.3 miles the second​ day, 1.9 miles the third​ day, and 3.1 miles the fourth d
JulsSmile [24]

Answer:

19.9 miles

Step-by-step explanation:

In this problem we have:

d_1=1 mi is the distance travelled during the 1st day

d_2=1.3 mi is the distance travelled during the 2nd day

d_3=1.9 mi is the distance travelled during the 3rd day

d_4=3.1 mi is the distance travelled during the 4th day

We notice that the difference between the distance travelled on the (n+1)-th day and the distance travelled on the n-th day doubles every day. In fact:

d_2-d_1=0.3\\d_3-d_2=2\cdot 0.3 = 0.6\\d_4-d_3=2\cdot 0.6 = 1.2

Which can be rewritten using the general formula:

d_{n+1}-d_n=2(d_n-d_{n-1})

This means that

d_{n+1}=d_n+2(d_n-d_{n-1})

By applying this formula recursively, we can find the 7th term, which is the distance travelled on the 7th day:

d_1=1\\d_2=1.3\\d_3=1.9\\d_4=3.1\\d_5=3.1+2\cdot 1.2=5.5\\d_6=5.5+2\cdot 2.4=10.3\\d_7=10.3+2\cdot 4.8=19.9 mi

So, the  distance travelled on the 7th day is 19.9 miles.

7 0
3 years ago
Ariel wants to find out the most popular theme for spirit week at school. She cannot decide between two methods.
fredd [130]
Option 2 as you get a wider range of student
8 0
3 years ago
Read 2 more answers
f is an even function. a = A 2-column table with 4 rows. Column 1 is labeled x with entries negative 2, 0, 2, 3. Column 2 is lab
Lady_Fox [76]

The values of a and b are 4 and -3

<h3>How to solve for (a) and (b)?</h3>

To solve for a, we make use of the function f(x).

x    f(x)

2     4

0     5

2     a

3     7

Remove the x values 0 and 3

x    f(x)

2     4

2     a

The above table implies that:

f(2) = 4 and f(2) = a

Substitute 4 for f(2) in f(2) = a

4 = a

Rewrite as:

a = 4

To solve for b, we make use of the function g(x).

x    g(x)

2     b

0     0

2     -3

3     -4

Remove the x values 0 and 3

x    g(x)

2     b

2     -3

The above table implies that:

f(2) = b and f(2) = -3

Substitute -3 for f(2) in f(2) = b

-3 = b

Rewrite as:

b = -3

Hence, the values of a and b are 4 and -3

Read more about functions at:

brainly.com/question/13153717

#SPJ1

<u>Complete question</u>

Use the Symmetry of a Function to Find Coordinates

f is an even function             g is an odd function

x    f(x)                                        x             g(x)

2     4                                          2              b

0     5                                          0              0

2     a                                          2              -3

3     7                                          3              -4

Find a and b

4 0
2 years ago
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