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den301095 [7]
3 years ago
14

Which biased estimator will have a reduced bias based on an increased sample size? mean median standard deviation range

Mathematics
1 answer:
alexgriva [62]3 years ago
8 0
The answer is: [C]: standard deviation ..
___________________________________
Explanation:
___________________________________
However, note that the mean of a sample from a normal population (that is, a type of "standard deviation" known as "standard deviation from a sample mean", is an "unbiased estimator" of the "population mean".

We shall represent the "sample mean" as:  x̅<span>  ; 
               (pronounced: "x-bar"; that is; "ex-bar"); this is the usual symbol                                                                                                              used; 
</span>
We shall represent the sample size as "n" ;
                                                 (This is the usual variable used; note that
                                                                                "n" is a numeric value).
__________________________________________________________
The standard deviant from the sample mean:

(n *  x̅)  / (n + 1) is a "biased estimator of the mean" that becomes "unbiased" as the sample size increases; since as "n" increases in values; the value of the entire entire expression becomes smaller (i.e the standard deviation becomes smaller.
___________________________
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Step-by-step explanation:

Given

The radius of the hemisphere is r=3.8\ in.

The volume of a hemisphere is given by

V=\dfrac{2}{3}\pi r^3

Insert the value

V=\dfrac{2}{3}\pi \times (3.8)^3\\\\V=114.9\ in.^3

7 0
3 years ago
Erica knits 18 squares on Monday. She knits 7 more squares each day for the rest  of the week. How many  squares does Erica have
Ne4ueva [31]
She knits 18 squares on Monday.
Then she knits 7 more squares each day:
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7 0
3 years ago
According to a study conducted by the Gallup Organization, the the proportion of Americans who are afraid to fly is 0.10. A rand
notsponge [240]

Answer: 0.1457

Step-by-step explanation:

Let p be the population proportion.

Given: The proportion of Americans who are afraid to fly is 0.10.

i.e. p= 0.10

Sample size : n= 1100

Sample proportion of Americans who are afraid to fly =\hat{p}=\dfrac{121}{1100}=0.11

We assume that the population is normally distributed

Now, the probability that the sample proportion is more than 0.11:

P(\hat{p}>0.11)=P(\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}>\dfrac{0.11-0.10}{\sqrt{\dfrac{0.10(0.90)}{1100}}})\\\\=P(z>\dfrac{0.01}{0.0090453})\ \ \ [\because z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}} ]\\\\=P(z>1.1055)\\\\=1-P(z\leq1.055)\\\\=1-0.8543=0.1457\ \ \ [\text{using z-table}]

Hence, the probability that the sample proportion is more than 0.11 = 0.1457

3 0
3 years ago
An object has a mass of 18 grams and its volume is 2 cm3 calculate density
Anna [14]
The density is 9 g/cm3
6 0
3 years ago
Read 2 more answers
Can someone please help me with this (it says I have to choose more than 1 answers)
Brrunno [24]

Answer:

B & C

Step-by-step explanation:

Since x is greater than 38, 40 and 120 matches the condition.

Hope u understand.

Please mark as the brainliest

7 0
3 years ago
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