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kotegsom [21]
3 years ago
9

Helppo please PLSS PLSS

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
7 0
Answer:m1=-3,m2=3 the equation has 2 solutions
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Gina saw twice as many tigers as lions at the zoo. The number of bears she saw was 7 less than the number of tigers. She saw fiv
Fynjy0 [20]
Gina saw 25 monkeys 
25 ÷ 5 = 5 
5 + 7 = 12
12 + 6 = 18
25 + 5 +12 + 6 = 48 animals 
gina saw 48 animals at the zoo
8 0
2 years ago
Jeremy swims 5 3/5 kilometers in a 7 day period. He swims the same distance each day. What distance does he swim?
PIT_PIT [208]
Since 5 3/5 can be turned into 28/5, then divided by 7/1, you will get 4/5. So Jeremy swims 4/5 of a kilometer each day.
4 0
3 years ago
Read 2 more answers
6.Suppose the Gallup Organization wants to estimate the population proportion of those who think there should be a law that woul
drek231 [11]

Answer:

A sample of n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2 is needed, in which E is the desired margin of error, as a proportion. If we find a decimal value, we round up to the next whole number.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In a previous study of 1012 randomly chosen respondents, 374 said that there should be such a law.

This means that n = 1012, \pi = \frac{374}{1012} = 0.3696

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

How large a sample size is needed to be 95% confident with a margin of error of E?

A sample size of n is needed, and n is found when M = E.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

E = 1.96\sqrt{\frac{0.3696*0.6304}{n}}

E\sqrt{n} = 1.96\sqrt{0.3696*0.6304}

\sqrt{n} = \frac{1.96\sqrt{0.3696*0.6304}}{E}

(\sqrt{n})^2 = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2

n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2

A sample of n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2 is needed, in which E is the desired margin of error, as a proportion. If we find a decimal value, we round up to the next whole number.

4 0
3 years ago
PLEASE HELP ASAP ASAP
muminat

Answer:

slope = -1/12

Step-by-step explanation:

From the figure we can see that the line passes through 2 points which are

(-6,-1) and (6,-2)

Use the formula y2-y1/x2-x1

(-2-(-1))/6-(-6)

(-2+1)/6+6

-1/12

3 0
2 years ago
In the figure below, AB=AE, AC=AD and AP is perpendicular to BE. Prove that BC=DE.
NISA [10]

Step-by-step explanation:

1) In the figure, as AB is equal to AE, ABE is an equilateral triangle.

As AP is perpendicular to BE

=> AP is the height of the triangle ABE.

In an equilateral triangle, the median and the height is the same, so that AP is also the median of the triangle.

=> P is the midpoint of BE

=> PE = PB

2) In the figure, as AC = AD, so that ACD is an equilateral triangle.

As AP is perpendicular to BE,  so that it is perpendicular to CD as well

=> AP is the height of the triangle ACD

In an equilateral triangle, the median and the height is the same, so that AP is also the median of the triangle ACD.

=> P is the midpoint of CD

=> PC = PD

We have:

+) PB = PE

+) PC = PD

=> PB - PC = PE - PD => BC = DE

5 0
3 years ago
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