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alisha [4.7K]
3 years ago
8

6x²-3x+8x-6 Plz do grouping for it

Mathematics
1 answer:
Nat2105 [25]3 years ago
7 0

Answer:

6x^{2} +5x-6

Step-by-step explanation:

Keep 6x^{2} and group -3x+8x which becomes 5x. Then keep -6.

Then it becomes the answer above.

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Find the area of the trapezoid .
sp2606 [1]

Answer:

303.66 in²

Step-by-step explanation:

The area (A) of a trapezoid is

A = \frac{1}{2} h (a + b)

where h is the perpendicular height and a, b the parallel bases

here h = 12.6, a = 19 and b = 29.2, so

A = 0.5 × 12.6 × (19 + 29.2)

  = 0.5 × 12.6 × 48.2 = 303.66 in²

4 0
3 years ago
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What is the standard form of twenty-two ten thousandths?
insens350 [35]
Twenty-two ten thousandths is
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3 years ago
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A. f(x) = 2|2| is differentiable overf<br> X<br> B. g(x) = 2 + || is differentiable over<br> -f
kramer

Recall the definition of absolute value:

• If <em>x</em> ≥ 0, then |<em>x</em>| = <em>x</em>

• If<em> x</em> < 0, then |<em>x</em>| = -<em>x</em>

<em />

(a) Splitting up <em>f(x)</em> = <em>x</em> |<em>x</em>| into similar cases, you have

• <em>f(x)</em> = <em>x</em> ² if <em>x</em> ≥ 0

• <em>f(x)</em> = -<em>x</em> ² if <em>x</em> < 0

Differentiating <em>f</em>, you get

• <em>f '(x)</em> = 2<em>x</em> if <em>x</em> > 0 (note the strict inequality now)

• <em>f '(x)</em> = -2<em>x</em> if <em>x</em> < 0

To get the derivative at <em>x</em> = 0, notice that <em>f '(x)</em> approaches 0 from either side, so <em>f</em> <em>'(x)</em> = 0 if <em>x</em> = 0.

The derivative exists on its entire domain, so <em>f(x)</em> is differentiable everywhere, i.e. over the interval (-∞, ∞).

(b) Similarly splitting up <em>g(x)</em> = <em>x</em> + |<em>x</em>| gives

• <em>g(x)</em> = 2<em>x</em> if <em>x</em> ≥ 0

• <em>g(x)</em> = 0 if <em>x</em> < 0

Differentiating gives

• <em>g'(x)</em> = 2 if <em>x</em> > 0

• <em>g'(x)</em> = 0 if <em>x</em> < 0

but this time the limits of <em>g'(x)</em> as <em>x</em> approaches 0 from either side do not match (the limit from the left is 0 while the limit from the right is 2), so <em>g(x)</em> is differentiable everywhere <u>except</u> <em>x</em> = 0, i.e. over the interval (-∞, 0) ∪ (0, ∞).

5 0
3 years ago
O.<br> What is the greatest common factor (GCF) of 4 and 64?
Fantom [35]

Answer:

yes .

.... I think 4 is the GCF of 4&64

8 0
3 years ago
One troop member So tickets for 33 crab meals and 20 vegetarian meals with a total receipt of $2025 another sold tickets for 30
natima [27]

Answer:

Therefore the cost of a crab meal and a vegetarian are $40.41 and $1.94 respectively.

Step-by-step explanation:

Given that,tickets for 33 crab meals and 20 vegetarian meal with total receipt of $2025. Another sold ticket for 30 crab meal and 11 vegetarian meals with total receipt of $1827.

Let the cost of a crab meal and a vegetarian meal be x and y respectively.

The cost of a crab meal is x

The cost of 33 crab meal is $33x

The cost of 30 crab meal is $30x

The cost of a vegetarian meal is y.

The cost of 20 vegetarian meal is $20y.

The cost of 11 vegetarian meal is $11y

According to problem,

33x+20y=2025

33x+20y-2025=0........(1)

        and

30x+11y=1827

30x+11y-1827=0 ..........(2)

Cross Multiplication Method,

a_1x+b_1y+c_1=0

a_2x+b_2y+c_2=0

\frac{x}{b_1c_2-b_2c_2}=\frac{y}{a_2c_1-a_1c_2}=\frac{1}{a_1b_2-a_2b_1}

{x}=\frac{b_1c_2-b_2c_2}{a_1b_2-a_2b_1}

{y}=\frac{a_2c_1-a_1c_2}{a_1b_2-a_2b_1}

Here a_1=33,b_1=20,c_1=-2025, a_2=30,b_2=11,c_2=-1827

\therefore x=\frac{20.(-1827)-11.(-2025)}{33.11-30.20}                   y=\frac{30.(-2025)-33.(-1827)}{33.11-30.20}

     \approx 40.41                                              \approx 1.94

Therefore the cost of a crab meal and a vegetarian are $40.41 and $1.94 respectively.

8 0
3 years ago
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