Answer:
2(47m^3-16n^3)
Step-by-step explanation:
Factors are: 0, 1, 2, 4, 8, 16
To answer this question, use permutation since the order of the letter matters. There are 7 letters and only 4 are to be used for the code. This is a permutation of 7 taken 4 (7P4) which is equal to 840. Thus, the sample space is 840.
For the next questions, there are 3 vowels for as the first letter, only 6 letters are available for the second, 5 on the next, and 4 on the last. Multiplying these numbers give 360. To solve for probability, divide this number with the sample space. Thus, the answer is 3/7.
Let us suppose number of rides is x.One ride costs $0.50.
Cost of x rides is 0.50x. The carnival charges is $5. Alex has $15 to spend .
Number of rides at most Alex can have can be given by the inequality:
0.50x+5≤ 15
To solve for x we subtract 5 both sides
0.50x≤ 15-5
0.50x≤ 10
Dividing both sides by 0.50 we have :
x≤ 20
Number of rides at most Alex can have is 20.
Answer:
72.51
Step-by-step explanation:
Given that :
Lab score % = 23%
Each Major test % = 22.5%
Final exam % = 32%
Score :
Lab score = 96
First Major test = 64
Second major test = 62
Final exam = 69
Hence,
Weighted average = Σ(weight % * score)
Weighted average = Σweight_1*score_1 +.. Weight_n * score_n)
(0.23 * 96) + (0.225 * 64) + (0.225 * 62) + (0.32 * 69) = 72.51
