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gogolik [260]
3 years ago
13

Find the value of k please! (There is a value and it’s not 14)

Mathematics
2 answers:
skelet666 [1.2K]3 years ago
8 0

Answer:

K=0

Step-by-step explanation:

14xk

k=0

14x0=10

Misha Larkins [42]3 years ago
5 0

Answer: k = 0

Step-by-step explanation:

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Solve for x using the quadratic formula. 4x^2-3x+8=0
Paraphin [41]

Answer:

answer : x = 3±√ 119 / 16

is correct answer ...plz mark my answer as brainlist ... plzzzz and plz vote me as brainlist

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Ummm help ig please................
AlexFokin [52]

Answer:

Cost of 500 g of standard pack = € 7.50

Cost of 1 g of standard pack = 7.50/500

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2 years ago
Amir has RM565. He spent all his money buying b pieces of clothing which cost Rm70 per piece and k pairs of shoes which cost RM9
agasfer [191]

Answer:

70b+95k=565. I think it's like this

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2 years ago
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The diagram below shows the graph of the quadratic function f (x) = ax² + 8x + c. calculate the value for each of the following.
Alexxandr [17]

Answer:

see explanation

Step-by-step explanation:

The y- intercept is at (0, 6) ⇒ c = 6

The x- coordinate of the vertex is at the midpoint of the zeros, that is

m = \frac{-3-1}{2} = \frac{-4}{2} = - 2

Since the zeros are x = - 3 and x = - 1 then the factors are (x + 3), (x + 1) and

f(x) = a(x + 3)(x + 1) = a(x² + 4x + 3)

Comparing with f(x) = ax² + 8x + 6 ⇒ a = 2

Thus

f(x) = 2x² + 8x + 6

Substitute m = - 2 into the equation for value of n

n = 2(- 2)² + 8(- 2) + 6 = 8 - 16 + 6 = - 2

Hence

c = 6, m = - 2, a = 2, n = - 2

3 0
3 years ago
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John and Jane are married. The probability that John watches a certain television show is .7. The probability that Jane watches
ikadub [295]

a) The probability  that both John and Jane watch the show is 0.12.

b.The probability that Jane watches the show, given that John does is  0.1714.

c)They do watch show independent of each other.

Step-by-step explanation:

Here, as given in the question:

Probability that John watches a certain show  = 0.7   ⇒ P(J) = 0.7

Probability that Jane watches a certain show  = 0.3   ⇒ P(Je) = 0.3

Probability that John watches a certain show given Jane watches it to

 = 0.4   ⇒ P(J/Je) = 0.4

a. )  Here, we need to find the probability of  both Jane and John watching a show , P(J∩Je)

Now, by BAYES THEOREM:

P(J/Je)  = \frac{P(J \cap Je)}{P(Je)}

\implies  0.4  = \frac{P(J \cap Je)}{0.3} \\\implies P(J \cap Je) = 0.4 \times 0.3  = 0.12

Hence the probability  that both John and Jane watch the show is 0.12.

b.) The probability that Jane watches the show, given that John does is P(J/Je)

By BAYES Theorem:

P(Je/J)  = \frac{P(J \cap Je)}{P(J)}\\\implies P(Je/J)  = \frac{0.12}{0.7}  = 0.1714

Hence, the probability that Jane watches the show, given that John does is  0.1714.

c) As we can see P(Jane ∩ John) =  0.12

So, the probability of both of them seeing the show TOGETHER is 0.12.

Hence, they do watch show independent of each other and the probability of doing that is 1.0.12  = 0.88

7 0
3 years ago
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