N the diagram, point O is the center of the circle and mADB = 43°. If mAOB = mBOC, what is mBDC?
1 answer:
The answer is 43°
Angle ADB is an inscribed angle which means arc AB has an angle twice that of angle ADB. The angle of the arc would be the same as that of the central angle AOB. So, mAOB = 86°. And since, mAOB = mBOC, then mBOC = 86° and arc BC has a measure of 86° as well. Angle BDC intercepts the arc BC which means half of the angle of arc BC is mBDC. So, mBDC = 43.
Angle ADB is an inscribed angle which means arc AB has an angle twice that of angle ADB. The angle of the arc would be the same as that of the central angle AOB. So, mAOB = 86°. And since, mAOB = mBOC, then mBOC = 86° and arc BC has a measure of 86° as well. Angle BDC intercepts the arc BC which means half of the angle of arc BC is mBDC. So, mBDC = 43.
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Answer:
The value of x = 4
Step-by-step explanation:
In this question, we are asked to calculate the value of the angle x
Here the ray cuts the angle into half.
Since the total of the angle was 120, half of this would be 120/2 = 60
Now, it is this value of 60, that our new angle equals to
Mathematically;
3x + 48 = 60
3x = 60-48
3x = 12
x = 12/3
x = 4
