N the diagram, point O is the center of the circle and mADB = 43°. If mAOB = mBOC, what is mBDC?
1 answer:
The answer is 43°
Angle ADB is an inscribed angle which means arc AB has an angle twice that of angle ADB. The angle of the arc would be the same as that of the central angle AOB. So, mAOB = 86°. And since, mAOB = mBOC, then mBOC = 86° and arc BC has a measure of 86° as well. Angle BDC intercepts the arc BC which means half of the angle of arc BC is mBDC. So, mBDC = 43.
Angle ADB is an inscribed angle which means arc AB has an angle twice that of angle ADB. The angle of the arc would be the same as that of the central angle AOB. So, mAOB = 86°. And since, mAOB = mBOC, then mBOC = 86° and arc BC has a measure of 86° as well. Angle BDC intercepts the arc BC which means half of the angle of arc BC is mBDC. So, mBDC = 43.
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Answer:
Option A. 264 ft² ; 4 gallons
Step-by-step explanation:
Given question is incomplete; find the complete question in the attachment.
From the picture attached,
Area of the barn to be painted = Area of the (rectangular base + Triangular top) - Area of the window
Area of the rectangular base = 12 × 18
= 216 ft²
Area of the triangular top =
=
= 60 square feet
Area of the window = 3 ft × 4 ft
= 12 ft²
Total area to be painted = 216 + 60 - 12
= 264 ft²
∵ 70 square feet of the barn is covered by the amount of paint = 1 gallon
∴ 1 square feet will be covered by the amount = gallons
∴ 264 square feet will be painted by =
= 3.77 gallons
≈ 4 gallons
Therefore, Option (A). 264 ft²; 4 gallons will be the answer.
Down 2 up 1 over 4 and do the same for the other side so that’s the equation on a graph
