N the diagram, point O is the center of the circle and mADB = 43°. If mAOB = mBOC, what is mBDC?
1 answer:
The answer is 43°
Angle ADB is an inscribed angle which means arc AB has an angle twice that of angle ADB. The angle of the arc would be the same as that of the central angle AOB. So, mAOB = 86°. And since, mAOB = mBOC, then mBOC = 86° and arc BC has a measure of 86° as well. Angle BDC intercepts the arc BC which means half of the angle of arc BC is mBDC. So, mBDC = 43.
Angle ADB is an inscribed angle which means arc AB has an angle twice that of angle ADB. The angle of the arc would be the same as that of the central angle AOB. So, mAOB = 86°. And since, mAOB = mBOC, then mBOC = 86° and arc BC has a measure of 86° as well. Angle BDC intercepts the arc BC which means half of the angle of arc BC is mBDC. So, mBDC = 43.
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Answer:
C
Step-by-step explanation:
The table shows a linear function.
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m =
with (x₁, y₁ ) = (1, 3) and (x₂, y₂ ) = (2, 7) ← 2 ordered pairs from the table
m = = 4, thus
y = 4x + c ← is the partial equation
To find c substitute any ordered pair into the partial equation
Using (1, 3), then
3 = 4 + c ⇒ c = 3 - 4 = - 1
y = 4x - 1 → C