Which of the following is graphed below

Question 6 (4 points)

riadik2000 [5.3K]

Answer:

Interior Angles: 3, 4, 5, 6

Exterior Angles 1, 2, 7, 8

Hope this helps!

3 0

2 years ago

Major help please !!!!!!!

ExtremeBDS [4]

3 5/9 divided by -2 2/3

change the mixed numbers to improper fractions

3 5/9 = (9*3+5)/9 = 32/9

-2 2/3 = -(3*2+2)/3 = -8/3

32/9 divided by -8/3

copy dot flip

32/9 * -3/8

-96/72

divide top and bottom by 24

-4/3

=-1 1/3

Answer: - 1 1/3

4 0

2 years ago

Please help me with this ASAP.

Ber [7]

Look at the attached picture ⤴

Hope it will help u...

But I can't see the question no.26 clearly ....

so text the question in comment box.

6 0

2 years ago

A random sample of 144 recent donations at a certain blood bank reveals that 81 were type A blood. Does this suggest that the ac

Reptile [31]

Answer:

Null hypothesis: $p=0.4$

Alternative hypothesis: $p \neq 0.4$

$z=\frac{0.5625 -0.4}{\sqrt{\frac{0.4(1-0.4)}{144}}}=3.98$

$p_v =2*P(z>3.98)=0.0000689$

Since the p value is very low compared to the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true percent of people with type A of blood is significantly different from 0.4 or 40%

Step-by-step explanation:

Information given

n=144 represent the random sample taken

X=81 represent the number of people with type A blood

$\hat p=\frac{81}{144}=0.5625$ estimated proportion of people with type A blood

$p_o=0.4$ is the value that we want to verify

$\alpha=0.01$ represent the significance level

z would represent the statistic

$p_v{/tex} represent the p value Hypothesis to testWe want to test if the percentage of the population having type A blood is different from 40%.: Null hypothesis:[tex]p=0.4$

Alternative hypothesis: $p \neq 0.4$

the statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info given we got:

$z=\frac{0.5625 -0.4}{\sqrt{\frac{0.4(1-0.4)}{144}}}=3.98$

Now we can calculate the p value with this probability taking in count the alternative hypothesis:

$p_v =2*P(z>3.98)=0.0000689$

Since the p value is very low compared to the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true percent of people with type A of blood is significantly different from 0.4 or 40%

3 0

2 years ago

Can someone please help , I have no idea at all :((

frez [133]

D=62*
triangles=180*
use the equation 90+28+d=180

8 0

2 years ago