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4 years ago

(-4ab+2a-4)-(-6ab-4) find the difference

Mathematics

1 answer:

Natalka [10]4 years ago

8 0

$(-4ab+2a-4)-(-6ab-4)$

$-4ab+2a-4+6ab+4

 
$

$(-4ab+6ab)+2a+(-4+4)

 
$ $Gather \ like \ terms$

$2ab+2a

 
$

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I need to know the seconds

laiz [17]

Answer:

t = 3 seconds

Step-by-step explanation:

Here h(t) = -16t^2 + 144.

When the quarter hits the ground, its height will be 0 feet. Letting h(t) = 0 results in -16t^2 + 144 = 0, or 16t^2 = 144, or

144

t^2 = ------------ = 36/4 = 9 seconds^2

Therefore, the time, t, required for the quarter to hit the ground is t = √9, or t = 3 seconds

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3 years ago

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3 years ago

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3 years ago

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3 years ago

During a rock concert, the noise level (in decibels) in front row seats has a mean of 95 dB with a standard deviation of 8 dB. W

lorasvet [3.4K]

Answer:

$\frac{8}{9} *100= 88.89 \%$

So we have at least 88.89% of the noise level values within 3 deviation from the mean.

Step-by-step explanation:

For this case let define the random variable X as the noise level, we know the following properties for X:

$E(X) = 95 , Sd(X)= 8$

And for this case we don't know the distribution for the random variable X.

But we can use the Chebysev theorem who states that the minimum percentage of the data that lies within k standard deviations from the mean is given by:

$1 -\frac{1}{k^2}, k>1$

So for this case we have that k = 3 and if we use this theorem we have:

$1- \frac{1}{3^2}$

$1- \frac{1}{9}=\frac{8}{9}$

And we can convert this into % and we got:

$\frac{8}{9} *100= 88.89 \%$

So we have at least 88.89% of the noise level values within 3 deviation from the mean.

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4 years ago