The second question is number 3 for the polygon translation.
Question 3 is 2 units right and four units down.

We know that,
- Pythagoras theoram is given by : p² + b² = h²
- In a Pythagoras triplet, the longest side represents the hypotenuse of the triangle.
Then,
We should check that, whether the sum of squares of the smaller sides will be equal to the square of the third side or not. Then, we can determine the above easily.
Sum of squares of smaller sides:
= 6² + 8²
= 36 + 64
= 100
Square of longer side:
= 10²
= 100
Sum of squares of smaller sides = Square of longer side. Hence, 6,8,10 are Pythagorean triplets.
And we are done! :D
⛱️ 
Answer:
32 5/8 (or 32 and 5/8)
Step-by-step explanation:
Okay, so this problem is asking for us to solve this problem with the substitution of a variable: x = -4. Before we fully solve this problem, we need to replace all of those x variables with -4 so that it is easier to solve.
-7 1/4(-4) + 3 5/8.
To make this problem even easier to solve, let's turn these mixed numbers into improper fractions. To do this, multiply the denominator by the whole number. Then add the numerator to this number. The new number that you just got is now your new numerator for this number.
-29/4(-4) + 3 5/8.
Repeat the last step to turn the other mixed number into an improper fraction.
-29/4(-4) + 29/8.
Now let's multiply that -4 by 29/4. Because a whole number technically has a denominator of 1, we can now set up the next part of our problem. (The symbol * means multiplication since we can't use x since it is already being used as a variable in this equation.)
(-29/4 * -4/1) + 29/8.
29 + 29/8.
Now to solve the rest of this problem, let's convert the whole number of 29 so that it has a denominator of 8. This is that these two numbers are addable.
<u>29</u> x <u>8</u> = <u>232</u>
1 x 8 = 8
Now these numbers are addable. So:
232/8 + 29/8 = 261/8 = 32 5/8.
I hope that this helps.