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3 years ago

Jesuseduardomontiel0 avatar

Mathematics

1 answer:

AlexFokin [52]3 years ago

7 0

WOW JIMMY. THATS A BIG . BIG. BIG. NUT SACK

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What is 9+10? is it 21?

AleksandrR [38]

Answer:

I know the joke your trying to pull of :>

Step-by-step explanation:

But if u really need help it's 19

8 0

3 years ago

Read 2 more answers

· The volume of Olivia's rectangular lunchbox is 240 cubic inches. The lunchbox has a height of 3 inches, and its length is 2 in

miskamm [114]

The volume of a cuboid is = length × width × height.

Let the width of Olivia's lunch box be 'x'.

Hence the length of Olivia's lunch box shall be 'x + 2'

Also the height of the box is given as 3 inches.

The volume of the box is 240 in³

Substituting in the formula we get

$x(x+2)(3) =240$

Dividing by 3 on both sides

$x(x+2)=80$

Exapnding we get

$x^2+2x=80$

Subtracting 80 from both sides

$x^2+2x-80=0$

Factoring

$(x+10)(x-8)=0$

We get

x= -10 or x = 8

But x cannot be negative

So x = 8

Hence the width of the box is 8 inches.

7 0

4 years ago

Read 2 more answers

Animal populations are not capable of unrestricted growth because of limited habitat and food supplies. Under such conditions th

trasher [3.6K]

Answer:

(a) 100 fishes

(b) t = 10: 483 fishes

t = 20: 999 fishes

t = 30: 1168 fishes

(c)

$P(\infty) = 1200$

Step-by-step explanation:

Given

$P(t) =\frac{d}{1+ke^-{ct}}$

$d = 1200\\k = 11\\c=0.2$

Solving (a): Fishes at t = 0

This gives:

$P(0) =\frac{1200}{1+11*e^-{0.2*0}}$

$P(0) =\frac{1200}{1+11*e^-{0}}$

$P(0) =\frac{1200}{1+11*1}$

$P(0) =\frac{1200}{1+11}$

$P(0) =\frac{1200}{12}$

$P(0) = 100$

Solving (a): Fishes at t = 10, 20, 30

$t = 10$

$P(10) =\frac{1200}{1+11*e^-{0.2*10}} =\frac{1200}{1+11*e^-{2}}\\\\P(10) =\frac{1200}{1+11*0.135}=\frac{1200}{2.485}\\\\P(10) =483$

$t = 20$

$P(20) =\frac{1200}{1+11*e^-{0.2*20}} =\frac{1200}{1+11*e^-{4}}\\\\P(20) =\frac{1200}{1+11*0.0183}=\frac{1200}{1.2013}\\\\P(20) =999$

$t = 30$

$P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168$

Solving (c): $\lim_{t \to \infty} P(t)$

In (b) above.

Notice that as t increases from 10 to 20 to 30, the values of $e^{-ct}$ decreases

This implies that:

${t \to \infty} = {e^{-ct} \to 0}$

So:

The value of P(t) for large values is:

$P(\infty) = \frac{1200}{1 + 11 * 0}$

$P(\infty) = \frac{1200}{1 + 0}$

$P(\infty) = \frac{1200}{1}$

$P(\infty) = 1200$

5 0

3 years ago

What is the purpose of "completing the square"?

zysi [14]

Step-by-step explanation:

When you complete the square, you change the equation so that the left side of the equation is a perfect square trinomial. But mainly completing the square is a technique that transforms your quadratic equation from an equation that can't be factored into one that can.

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3 years ago

Help if you would like brainliest

gladu [14]

1. $2.78

2. If it’s 20% off you save 13.90 so 69.50- 13.90 is $55.60

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3 years ago