Hey there :) I'm pretty sure that your answer is D) ∠S ≅ <span>∠Y because corresponding angles of similar triangles are congruent.
I think that it is the answer because if you shift your paper around, and look at the angles from different views, you can tell that angles S and Y are congruent, or the same, because of the way that both angles are at the end of the longer sides of both triangles.
So, your answer is D!
~Hope this helped!~</span>
Answer:
Step-by-step explanation:
3 Triangle
4 Quadrilateral
5 Pentagon
6 Hexagon
7 Heptagon
8 Octagon
9 Nonagon
10 Decagon
Answer:
2(2 +5)
Step-by-step explanation:
We presume you want to rewrite the expression making use of the distributive property. For that, it is helpful to find a factor common to the two terms. The GCD of 4 and 10 is 2, so we can factor that out:
4 + 10 = 2(2 +5)
_____
Of course, you can use any factor you like. It doesn't need to be an integer.
= (1/3)(12 +30)
= 0.4(10 +25)
= 4(1 +2.5)
When finding the domain of a square root, you have to know that it is impossible to get the square root of 0 or any negative number. since domain is possible x values this means that x cannot be 0 or any number less than 0. However, you can find the square root of the smallest most infinitely small number greater than 0. since an infinitely small number close to zero can not be written out, we must must say that the domain starts at 0 exclusive. exclusive is represented by an open or close parenthesis so in this case the domain starts with:
(0,
we can get the square root of any number larger than 0 up to infinity but infinity can never be reached so it is also exclusive. So so the ending of our domain would be:
,infinity)
So the answer if the square root is only over the x the answer is
(0, infinity)
But if the square root is over the x- 5 then this would brIng a smaller amount of possible x values. since anything under the square root sign has to be greater than 0, you can say that:
(x - 5) > 0
x > 5
Therefore the domain would start at 5 and the answer would be:
(5, infinity)
