A straight line is 180°.
The sum of all the angles in a triangle is also 180°.
Let the missing angle be x°.
For the straight line:
x + 2x²+ 3x+ 6 = 180
x = 180 - (2x² + 3x + 6)
x = 180 - 2x² - 3x - 6
x = 174 - 2x² - 3x
For the missing angle in the triangle:
(174 - 2x² - 3x) + 8x + 3x² - 6x = 180
174 - 2x² - 3x + 8x + 3x² - 6x = 180
174 + x² - x = 180
x² - x + 174 - 180 = 0
x² - x - 6 = 0
(x + 2)(x - 3) = 0
x + 2 = 0 or x - 3 = 0
x = -2 or x = 3
The answer is x = -2 or x = 3
Answer:
C
Step-by-step explanation:
The values are not vectors so ST/SR should be 3
Answer:
<em>g(</em><em>x)</em><em> </em><em>=</em><em> </em><em>-4g(</em><em>x)</em><em> </em><em>=</em><em> </em><em>-x+</em><em>4</em>
<em>=</em><em> </em><em>g(</em><em>5</em><em>)</em><em> </em><em>=</em><em> </em><em>-</em><em>4</em><em>(</em><em>5</em><em>)</em><em> </em><em>=</em><em> </em><em>-</em><em>(</em><em>5</em><em>)</em><em>+</em><em>4</em>
<em>=</em><em> </em><em>g(</em><em>5</em><em>)</em><em> </em><em>=</em><em> </em><em>-</em><em>2</em><em>0</em><em> </em><em>=</em><em> </em><em>-</em><em>1</em>
Answer:
this is the equation of the tangent at point (-1,1/e)
Step-by-step explanation:
to find the tangent line we need to find the derivative of the function g(x).
- we know that
this the equation of the slope of the curve at any point x and it also the slope of the tangent at any point x. hence, g'(x) can be denoted as 'm'
to find the slope at (-1,1/e) we'll use the x-coordinate of the point i.e. x = -1
using the equation of line:
we'll find the equation of the tangent line.
here (x1,y1) =(-1,1/e), and m = 3/e
this is the equation of the tangent at point (-1,1/e)
