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lana66690 [7]
3 years ago
10

A ferry departs from a port along the Sands River at 10:00 am. The ferry travels at a speed of 15 mph in still water and returns

to port at 2:00 pm. If the ferry trip upstream takes twice as long as its return trip downstream, what is the speed of the river’s current
Mathematics
1 answer:
jek_recluse [69]3 years ago
8 0

Answer:

Speed of river's current = 5 mph

Step-by-step explanation:

Let 'd' be the distance covered  

 Let x be the speed of the rivers current

Speed upstream = 15-x

speed downstream = 15+x

Time = distance / speed

time upstream = \frac{d}{15-x}

time downstream = \frac{d}{15+x}

the ferry trip upstream takes twice as long as its return trip downstream

\frac{d}{15-x}= \frac{2d}{15+x}

divide both sides by d

\frac{1}{15-x}= \frac{2}{15+x}

cross multiply

15+x= 2(15-x)

15+x= 30-2x

Add 2x on both sideds

15+3x= 30

subtract 15 from both sides and divide by 3

3x=15

x=5

Speed of river's current = 5 mph

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