2 years ago

Solve the simultaneous equation y = x^2 and y = 3x - 2

1 answer:

3 0

Answer:

${x}^{2} = 3x - 2 \\ {x}^{2} - 3x + 2 = 0 \\ (x - 1)(x - 2) = 0 \\ x = 1 \: or \: x = 2 \\ for \: x \: = 1 \\ \: y = {(1)}^{2} = 1 \\ for \: x = 2 \\ y = {(2)}^{2} = 4$

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