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Vikki [24]
3 years ago
6

Find the value of x. If necessary, round to the nearest tenth

Mathematics
1 answer:
Luden [163]3 years ago
5 0

Answer:

8

Step-by-step explanation:

→ Use trigonometry to find x, we have no hypotenuse so we utilise the TOA formula

TOA = Tan = Opposite ÷ Adjacent

→ The opposite of the triangle is 8√3 and we want to find the adjacent of this triangle so we rearrange

Opposite ÷ Tan

→ Substitute in the values

8√3 ÷ tan(60) = 8

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What sum will amount to rupees 4000 in 3 years at 6% p.a. compound interest​
natali 33 [55]

Answer:

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{purple}{Given:}}}}}}}\end{gathered}

  • ⇢ Principle = Rs.4000
  • ⇢ Rate = 6%
  • ⇢ Time = 3 year

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{purple}{To Find:}}}}}}}\end{gathered}

  • ⇢ Amount

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{purple}{Using Formula:}}}}}}}\end{gathered}

{\dag{\underline{\boxed{\sf{Amount  ={P{\bigg(1 + \dfrac{R}{100}{\bigg)}^{T}}}}}}}}

\dag{\underline{\boxed{\sf{Compound \: Interest = Amount- Principle }}}}

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{purple}{Solution:}}}}}}}\end{gathered}

{\bigstar \:{\underline{\pmb{\frak{\red{Firstly,Finding  \: the  \: Amount }}}}}}

\quad {:\implies{\sf{Amount  = \bf{P{\bigg(1  +  \dfrac{R}{100}{\bigg)}^{T}}}}}}

  • Substituting the values

\quad {:\implies{\sf{Amount  = \bf{4000{\bigg(1  +  \dfrac{6}{100}{\bigg)}^{3}}}}}}

\quad {:\implies{\sf{Amount  = \bf{4000{\bigg(1 \times 100  +  \dfrac{6}{100}{\bigg)}^{3}}}}}}

\quad {:\implies{\sf{Amount  = \bf{4000{\bigg( \dfrac{100 + 6}{100}{\bigg)}^{3}}}}}}

\quad {:\implies{\sf{Amount  = \bf{4000{\bigg( \dfrac{106}{100}{\bigg)}^{3}}}}}}

\quad {:\implies{\sf{Amount  = \bf{4000{\bigg({\cancel{\dfrac{106}{100}}{\bigg)}}^{3}}}}}}

\quad {:\implies{\sf{Amount  = \bf{4000{\bigg( \dfrac{53}{50}{\bigg)}^{3}}}}}}

\quad {:\implies{\sf{Amount  = \bf{4000{\bigg( \dfrac{53}{50} \times \dfrac{53}{50} \times \dfrac{53}{50}{\bigg)}}}}}}

\quad {:\implies{\sf{Amount  = \bf{4000{\bigg( \dfrac{148877}{125000}{\bigg)}}}}}}

\quad {:\implies{\sf{Amount  = \bf{4000 \times  \dfrac{148877}{125000}}}}}

\quad {:\implies{\sf{Amount  = \bf{4{\cancel{000}} \times  \dfrac{148877}{125{\cancel{000}}}}}}}

\quad {:\implies{\sf{Amount  = \bf{\dfrac{148877 \times 4}{125}}}}}

\quad {:\implies{\sf{Amount  = \bf{\dfrac{595508}{125}}}}}

\quad {:\implies{\sf{Amount  = \bf{\cancel{\dfrac{595508}{125}}}}}}

\quad {:\implies{\sf{Amount  = \bf{4764.064}}}}

\begin{gathered} \dag{\boxed{\textsf{\textbf{\underline{\color{green}{Amount = {Rs.4764.064}}}}}}}\end{gathered}

  • Hence, The Amount is Rs.4764.064

\begin{gathered}\end{gathered}

{\bigstar \:{\underline{\pmb{\frak{\red{ Now,Finding  \: The \:  Compound \:  Interest }}}}}}

\quad{: \implies{\sf{Compound \: Interest =  \bf{Amount- Principle }}}}

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\quad{: \implies{\sf{Compound \: Interest = \bf{4764.064- 4000 }}}}

\quad{: \implies{\sf{Compound \: Interest =\bf{764.064}}}}

\begin{gathered} \dag{\boxed{\textsf{\textbf{\underline{\color{green}{Compound Interest  = Rs.764.064}}}}}}\end{gathered}

  • Henceforth,The Compound Interest is Rs.764064

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{purple}{Learn More:}}}}}}}\end{gathered}

\begin{gathered}\begin{gathered}\begin{gathered} \dag \: \underline{\bf{More \: Useful \: Formula}}\\ {\boxed{\begin{array}{cc}\dashrightarrow {\sf{Amount = Principle + Interest}} \\ \\ \dashrightarrow \sf{ P=Amount - Interest }\\ \\ \dashrightarrow \sf{ S.I = \dfrac{P \times R \times T}{100}} \\ \\ \dashrightarrow \sf{P = \dfrac{Interest \times 100 }{Time \times Rate}} \\ \\ \dashrightarrow \sf{P = \dfrac{Amount\times 100 }{100 + (Time \times Rate)}} \\ \end{array}}}\end{gathered}\end{gathered}\end{gathered}

8 0
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Mrac [35]

Answer:

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Step-by-step explanation:

Given that;

The sample size = 1500

The sample proportion \hat p = 0.60

Confidencce interval = 0.95

The level of significance ∝ = 1 - C.I

= 1 - 0.95

= 0.05

The critical value:

Z_{\alpha/2} = Z_{0.05/2} \\ \\  Z_{0.025} = 1.96 (From the z tables)

The margin of error is calculated by using the formula:

M.O.E = Z_{\alpha/2} \times \sqrt{\dfrac{\hat p(1 -\hat p)}{n}}

M.O.E = 1.96 \times \sqrt{\dfrac{\hat 0.60(1 -0.60)}{1500}}

M.O.E = 1.96 \times \sqrt{\dfrac{0.24}{1500}}

M.O.E = 1.96 \times \sqrt{1.6 \times 10^{-4}}

M.O.E = 0.02479

M.O.E ≅ 0.025

The margin of error M.O.E = 2.5%

8 0
3 years ago
Consider the words typically associated with geometry. Are there any words that would be hard to precisely define? What words ca
noname [10]

Answer:

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Step-by-step explanation:

Hope this helps! :)

8 0
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Write an equation in​ point-slope form of the line that passes through the given​ points, then write the equation in​ slope-inte
frosja888 [35]

As we go from (-6,6) to (9,1), x increases by 15 and y decreases by 5.  Thus, the slope of this line is m = rise / run = -5/15, or m = -1/3.

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6 = 2 + b.  Then b = 4, and the equation in slope-intercept form is

y = (-1/3)x + 4.

8 0
3 years ago
158÷37 show work need help
denis-greek [22]
Here’s a pic of my work, it shows that the numbers 2,7,0 repeat.

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8 0
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