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Vikki [24]
3 years ago
6

Find the value of x. If necessary, round to the nearest tenth

Mathematics
1 answer:
Luden [163]3 years ago
5 0

Answer:

8

Step-by-step explanation:

→ Use trigonometry to find x, we have no hypotenuse so we utilise the TOA formula

TOA = Tan = Opposite ÷ Adjacent

→ The opposite of the triangle is 8√3 and we want to find the adjacent of this triangle so we rearrange

Opposite ÷ Tan

→ Substitute in the values

8√3 ÷ tan(60) = 8

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The product of some negative number and 4 less than twice that number is 286 find the number
Naya [18.7K]
Let's say that number is hmmm "a"

now.. twice "a" is 2*a or 2a
4 less than that is " 2a - 4"

now, the product of those two fellows is 286, well ok

a( 2a - 4) = 286

thus    

\bf a(2a-4)=286\implies 2a^2-4a^2=286\implies a^2-2a^2=143
\\\\\\
a^2-2a^2-143=0\implies (a-13)(a+11)=0
\\\\\\
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5 0
3 years ago
If y varies directly as the x^2 and y = 200 when x = 5, what is the value of y when x = -3?
gayaneshka [121]
As the variation is direct we have:
 y = kx ^ 2

 We must find the value of k.
 For this, we use the following data:
 y = 200 when x = 5
 Substituting values we have:
 200 = k5 ^ 2

 Clearing k:
 k = 200/5 ^ 2

k = 200/25

k = 8
 Then, the function is:
 y = 8x ^ 2

 We evaluate the function for x = -3
 y = 8 (-3) ^ 2

y = 8 (9)

y = 72
 Answer:
 the value of y when x = -3 is:
 c.
 
72
6 0
3 years ago
WILL GIVE BRAINLYIST DUE IN 2 HOURS
Alja [10]

Answer:

Step-by-step explanation:

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4 0
3 years ago
Solve 2(x+3)3/2=54 x = <br>show your work
hjlf

Answer:

x=15

Step-by-step explanation:

Step 1: Multiply both sides by 2.

Step 2: Simplify both sides of the equation.

6x+18=108

Step 3: Subtract 18 from both sides.

6x+18−18=108−18

6x=90

Step 4: Divide both sides by 6.

x=15

6 0
3 years ago
A 6 cm long spring extends to 9 cm when a 1 kg load is suspended from it. What would be its length if a 2 kg load were suspended
vampirchik [111]

Answer:

12 cm

Step-by-step explanation:

To calculate the length of a spring with a 2 kg load, compare the displacement of a 1 kg load and adjust accordingly.

When a 1 kg load is suspended from the spring, the spring which is 6 cm stretches to 9 cm. This is 3 cm longer due to the weight. If you attach a weight which is twice as much then the displacement will be twice as much. Instead of stretching an additional 3 cm, it will stretch 2*3 = 6 cm. Add this to the length of the spring and it stretches in total 6 + 6 = 12 cm.

4 0
3 years ago
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