1/3x+y=9, -2x+2y= -6... what is x and y, using the substitution method?

1 answer:

Klio2033 [76]2 years ago

6 0

1/3x + y = 9
y = -1/3x + 9

-2x + 2y = -6
-2x + 2(-1/3x + 9) = -6
-2x - 2/3x + 18 = -6
-6/3x - 2/3x = -6 - 18
-8/3x = -24
x = -24 * -3/8
x = 9 <== here is y

-2x + 2y = -6
-2(9) + 2y = -6
-18 + 2y = -6
2y = -6 + 18
2y = 12
x = 12/2
x = 6 <=== here is x

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The diameter of a circle is 16 kilometers. Find the area of the circle.

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The diameter of a circle is 16 kilometers. Then the area of the circle is $201.062 \mathrm{km}^{2}$

Solution:

Given that , the diameter of a circle is 16 kilometers

We have to find the area of the circle .

Radius is half of diameter.

$\begin{array}{l}{\text { diameter }=2 \times \text { radius } \rightarrow \text { radius }=\frac{\text {diameter}}{2}} \\\\ {\rightarrow \text { radius }=\frac{16}{2} \rightarrow \text { radius }=8 \text { kilometers. }}\end{array}$

The area of circle is given as:

$\begin{array}{l}{\text { area of a circle }=\pi \times r^2 \\ {\text { Area of a circle }=\pi \times 8^{2}=\pi \times 64=64 \times 3.14=201.062}\end{array}$