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lbvjy [14]
3 years ago
11

Daniel wants to do 312 practice problems to prepare for an exam. If he wants to do approximately the same number of problems eac

h day for 36 days, which best describes the number of problems that he needs to do each day? mc012-1.jpg 8 problems per day for 12 of the days and 9 problems per day for 24 of the days 8 problems per day for 24 of the days and 9 problems per day for 12 of the days 8 problems per day for each of the days 9 problems per day for each of the days
Mathematics
2 answers:
Digiron [165]3 years ago
6 0
The first one because  if you set it up like this
(8*12)+(9*24)=
8*12=96
9*24=216
96+216=312

sergejj [24]3 years ago
3 0

Answer:

8 problems per day for 12 of the days and 9 problems per day for 24 of the days

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2 (3x+1)=17-3 (x-17)
elena-14-01-66 [18.8K]
<h2>Answer:</h2>

x =  \frac{22}{3}

<h3>alternative form:</h3>

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<h2>Step-by-step explanation:</h2>

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3 0
3 years ago
107,600 115,220 104,910 median, mode, mean
san4es73 [151]

Answer:

<u>1. Mean =  342.7 (Rounding to the nearest tenth)</u>

<u>2. Median =  167.5 </u>

<u>3. Mode = There isn't a mode for this set of numbers because there isn't a data value that occur more than once. </u>

Step-by-step explanation:

Given this set of numbers: 107, 600,  115, 220,  104, 910, find out these measures of central tendency:

1. Mean = 107 + 600  + 115 + 220 + 104 + 910/6 = <u>342.7</u> (Rounding to the nearest tenth)

2. Median. In this case, we calculate it as the average between the third and the fourth element, this way:

115 + 220 =335

335/2 = <u>167.5 </u>

3. Mode = <u>There isn't a mode for this set of numbers because there isn't a data value that occur more than once. All the data values occur only once.</u>

5 0
3 years ago
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