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tia_tia [17]
3 years ago
9

Will give 100 pts and brainliest

Mathematics
2 answers:
prohojiy [21]3 years ago
8 0

Answer:

y = \sqrt{19^2 + 8.2^2}

Step-by-step explanation:

to get the hypotenuse:

use the Pythagorean theorem:

a² + b² = c²

where a = 19,  b = 8.2  c = y

plugin values:

19² + 8.2² = y²

y = \sqrt{19^2 + 8.2^2}

Tom [10]3 years ago
7 0

Answer:

y =

Step-by-step explanation:

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If Joe drives 186.83 miles on a business trip, and the reimbursement from his company is $13.08. At what rate is Joe's employer
kirill115 [55]

Answer:

7 cents/mile

Step-by-step explanation:

You are looking for a unit rate of cents per mile.

Change the dollar amount to cents, and divide by the number of miles.

$13.08 * (100 cents)/$ = 1308 cents

(1308 cents)/(183 miles) = 7.001 cents/mile

8 0
3 years ago
“I think of a number, multiply it by 2, subtract 3 and multiply the result by 4."
Scorpion4ik [409]

Answer:

33x2=66

66-3=62

62x4=248

Is this a question for a test cause if it is i'm gonna feel embarrassed

5 0
3 years ago
If Clay can run one lap in a ¼ of an hour. How many hours will it take him to run 5 ⅓ laps around the track.​
Serjik [45]

Answer: 21

Step-by-step explanation

5 1/4 divided by 1/4

u simplify 5 1/4 =21/4

1/4=0.25

21/4 divided by 1/4 is 21

4 0
3 years ago
Imagine that you would like to purchase a $275,000 home. Using 20% as
vfiekz [6]

Answer:

The mortgage chosen is option A;

15-year mortgage term with a 3% interest rate because it has the lowest total amount paid over the loan term of $270,470

Step-by-step explanation:

The details of the home purchase are;

The price of the home = $275,000

The mode of purchase of the home = Mortgage

The percentage of the loan amount payed as down payment = 20%

The amount used as down payment for the loan = $55,000

The principal of the mortgage borrowed, P = The price of the house - The down payment

∴ P = $275,000 - 20/100 × $275,000 = $275,000 - $55,000 = $220,000

The principal of the mortgage, P = $220,000

The formula for the total amount paid which is the cost of the loan is given as follows;

Outstanding \ Loan \ Balance = \dfrac{P \cdot \left[\left(1+\dfrac{r}{12} \right)^n -  \left(1+\dfrac{r}{12} \right)^m \right] }{1 - \left(1+\dfrac{r}{12} \right)^n }

The formula for monthly payment on a mortgage, 'M', is given as follows;

M = \dfrac{P \cdot \left(\dfrac{r}{12} \right) \cdot \left(1+\dfrac{r}{12} \right)^n }{\left(1+\dfrac{r}{12} \right)^n - 1}

A. When the mortgage term, t = 15-years,

The interest rate, r = 3%

The number of months over which the loan is payed, n = 12·t

∴ n = 12 months/year × 15 years = 180 months

n = 180 months

The monthly payment, 'M', is given as follows;

M =

The total amount paid over the loan term = Cost of the mortgage

Therefore, we have;

220,000*0.05/12*((1 + 0.05/12)^360/( (1 + 0.05/12)^(360) - 1)

M = \dfrac{220,000 \cdot \left(\dfrac{0.03}{12} \right) \cdot \left(1+\dfrac{0.03}{12} \right)^{180} }{\left(1+\dfrac{0.03}{12} \right)^{180} - 1}  \approx 1,519.28

The minimum monthly payment for the loan, M ≈ $1,519.28

The total amount paid over loan term, A = n × M

∴ A ≈ 180 × $1,519.28 = $273,470

The total amount paid over loan term, A ≈ $270,470

B. When t = 20 year and r = 6%, we have;

n = 12 × 20 = 240

\therefore M = \dfrac{220,000 \cdot \left(\dfrac{0.06}{12} \right) \cdot \left(1+\dfrac{0.06}{12} \right)^{240} }{\left(1+\dfrac{0.06}{12} \right)^{240} - 1}  \approx 1,576.15

The total amount paid over loan term, A = 240 × $1,576.15 ≈ $378.276

The monthly payment, M = $1,576.15

C. When t = 30 year and r = 5%, we have;

n = 12 × 30 = 360

\therefore M = \dfrac{220,000 \cdot \left(\dfrac{0.05}{12} \right) \cdot \left(1+\dfrac{0.05}{12} \right)^{360} }{\left(1+\dfrac{0.05}{12} \right)^{360} - 1}  \approx 1,181.01

The total amount paid over loan term, A = 360 × $1,181.01 ≈ $425,163

The monthly payment, M ≈ $1,181.01

The mortgage to be chosen is the mortgage with the least total amount paid over the loan term so as to reduce the liability

Therefore;

The mortgage chosen is option A which is a 15-year mortgage term with a 3% interest rate;

The total amount paid over the loan term = $270,470

8 0
3 years ago
How many solutions does 15x+12y=18 have
dangina [55]

Answer: 2 or more.

X and Y could be anything, so there are at least two answers

8 0
3 years ago
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