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Neko [114]
3 years ago
12

From 11:50 a.m. to 12:40 p.m. is

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
6 0

If you’re wondering the minutes in between it would be 50 minutes from 11:50am to 12:40pm

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Combine the like terms to make a simpler expression: 5k (-2k)-(-1)
TiliK225 [7]
Hey there, Lets solve this problem together. 

Our first step will be to g<span>ather like terms 

</span>5*-2k*k+1 
<span>
 Simplify 5×−2k×k to −5×2k×k

</span>-5*2k*k+1 

Simplify <span><span>5×2k×k</span></span><span> to </span><span><span>10<span>k^2 

</span></span></span>-10k^2+1 <span><span><span>
</span></span></span>
7 0
3 years ago
Read 2 more answers
Ashton rode his bicycle 3.25 miles in 12 minutes. What was Ashton’s average rate in miles per hour?
dangina [55]

Answer:

Ashton rode his bicycle 3.25 miles in 12 minutes. What was Ashton's average rate in miles per hour? The answer is 16.25

Ive done this

7 0
3 years ago
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Jackie invests $25,000, part at 5.5% annual interest and the balance at 8.3% annual interest. how much is invested at each rate
Verizon [17]
I am soo sorry i have eno idea
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7 0
3 years ago
Help please! I’m giving brainliest to however gets this question right.
Arisa [49]

Answer:

They both have area 4

Step-by-step explanation:

Area of the square:

base*height = 2 * 2 = 4

Area of the triangle:

Using the left-side of the triangle as the base, and the height from the left-side to the bottom-right corner:

\frac{1}{2}base*height

\frac{1}{2}4\sqrt2*\sqrt2=4

We know the length of the diagonal is \sqrt2 as we are using a centimetre grid, so we can create an isosceles triangle with side lengths 1 and our unknown length, we can then use Pythagorean Theorem to work out our unknown side length.

a^2+b^2=c^2

1^2+1^2=c^2

2=c^2

\sqrt2=c

7 0
3 years ago
Henry has a fenced yard in the shape of a rectangle with a perimeter that measures 242 feet. If the width of the yard measures 5
neonofarm [45]

Answer: Length = 70 feet

Concept:

Here, we need to know how to find the perimeter of a rectangle.

Perimeter (rectangle) = 2 (l + w)

l = length

w = width

Solve:

<u>Given information</u>

l = l

w = 51 feet

P = 242 feet

<u>Given expression</u>

P = 2 (l + w)

<u>Substitute values into the expression</u>

242 = 2 (l + 51)

<u>Divide 2 on both sides</u>

242 / 2 = 2 (l + 51) / 2

121 = l + 51

<u>Subtract 51 on both sides</u>

121 - 51 = l + 51 - 51

\boxed{l=70}

Hope this helps!! :)

Please let me know if you have any questions

4 0
3 years ago
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