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3 years ago

The measure of angle W is 100°, and the measure of angle Z is 68°

Mathematics

1 answer:

Novay_Z [31]3 years ago

7 0

Answer:

its 32 degrees

Step-by-step explanation:

w is a exterior angle which is the two interior angles sum farthest away from it. so Z+Y=W basically 100-68=32 which is y. y=32

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A (0, 2) and B (6,6) are points on the straight line ABCD.

elena-14-01-66 [18.8K]

Answer:

(18, 14)

Step-by-step explanation:

We know that C and D lie on the line AB and BC = CD = AB. Then we need to use the distance formula and equation of the line AB to find the other two coordinates.

The distance formula states that the distance between two points $(x_1,y_1)$ and $(x_2,y_2)$ , the distance is denoted by: $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ . Let's find the distance between A and B:

d = $\sqrt{(6-0)^2+(6-2)^2}=\sqrt{6^2+4^2} =\sqrt{36+16} =\sqrt{52} =2\sqrt{13}$

Now say the coordinates of D are (a, b). Then the distance between D and B will be twice of 2√13, which is 4√13:

4√13 = $\sqrt{(6-a)^2+(6-b)^2}$

Square both sides:

208 = (6 - a)² + (6 - b)²

Let's also find the equation of the line AB. The y-intercept we know is 2, so in y = mx + b, b = 2. The slope is (6 - 2) / (6 - 0) = 4/6 = 2/3. So the equation of the line is: y = (2/3)x + 2. Since (a, b) lines on this line, we can put in a for x and b for y: b = (2/3)a + 2. Substitute this expression in for b in the previous equation:

208 = (6 - a)² + (6 - b)²

208 = (6 - a)² + (6 - (2/3a + 2))² = (6 - a)² + (-2/3a + 4)²

208 = a² - 12a + 36 + 4/9a² - 16/3a + 16 = 13/9a² - 52/3a + 52

0 = 13/9a² - 52/3a - 156

13a² - 156a - 1404 = 0

a² - 12a - 108 = 0

(a + 6)(a - 18) = 0

a = -6 or a = 18

We know a can't be negative so a = 18. Plug this back in to find b:

b = 2/3a + 2 = (2/3) * 18 + 2 = 12 + 2 = 14

So point D has coordinates (18, 14).

8 0

2 years ago

Read 2 more answers

A glass of water was seven- eighths of a liter. With a 6 liter jug, how many glasses could you pour? Do you have to multiply div

ivolga24 [154]

Let us suppose, we pour x glass of water.

The given jug is of 6 liters. And the glass of water was seven- eighths of a liter. Hence, we have the below equation

$\frac{7}{8} x= 6$

Now, in order to solve for x, we will divide 6 with 7/8. So, we have to divide.

$x=\frac{6}{7/8} \\
\\
x=\frac{48}{7} \\
\\
x=6.9$

Hence, we can pour 7 glass of water. But the 7th glass is not full of water. It is partially full.

5 0

2 years ago

Find three consecutive integers such that that product of the first and third is one

Tema [17]

Answer:

n = the first

n + 1 = the 2nd

n + 2 = the 3rd

n(n + 2) - (n + 1) = 10(n + 2) + 1

n2 + 2n - n - 1 = 10n + 20 + 1

n2 - 9n - 22 = 0

(n - 11)(n + 2) = 0

If two factors = 0, at least one must = 0.

n - 11 = 0

n = 11

11,12,13

n + 2 = 0

n = -2

-2,-1,0

7 0

2 years ago

Which expression is equivalent to the quantity five raised to the negative second power times three raised to the fifth power en

serg [7]

The equivalent expression is 5^(4) * 3^(-10)

<h3>How to determine the equivalent expression?</h3>

The statement is given as:

five raised to the negative second power times three raised to the fifth power end quantity all raised to the negative second power

Rewrite properly as:

(5^-2 * 3^5)^-2

Expand the expression by multiplying the exponents

So, we have:

5^(-2 -2) * 3^(5 *-2)

Evaluate the products

5^(4) * 3^(-10)

Hence, the equivalent expression is 5^(4) * 3^(-10)