Question

When the function f(x) = 6(9)" is changed to fix) = 6(9)*+1, what is the effect?

Answer 1

Answer:

The y-intercept is one space higher

Step-by-step explanation:

Remember that the y-intercept is the value of y when the value of x is equal to zero (initial value)

we have

$f(x)=6(9^{x})$

For x=0

$f(0)=6(9^{0})=6$ ----> y-intercept

If the function is changed to

$f(x)=6(9^{x})+1$

For x=0

$f(0)=6(9^{0})+1=7$ ---> y-intercept

therefore

The y-intercept is one space higher