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tester [92]
2 years ago
14

15 POINT!!!!!!!!!!I NEED HELP IM FAILING

Mathematics
2 answers:
Katyanochek1 [597]2 years ago
8 0
The equation is y=-3.
MArishka [77]2 years ago
7 0

Answer:

Your answer would be "y=-3". The reason why is because it runs through the y-intercept of -3.

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Please help me with this!
stich3 [128]

Answer:

y = x^2 - 4x - 6.

Step-by-step explanation:

The roots are  2 + √10 and 2 - √10, so in factor form we have:

(x -  (2 + √10))(x - (2 - √10))

= ( x -  2 - √10)(x - 2 + √10)

= x^2 - 2x + √10x - 2x + 4 - 2√10 - √10x  + 2√10 - √100

=  x^2 -4x + 4 - 10

= x^2 - 4x - 6.

7 0
3 years ago
(2x² - 5) - (3x² + 4).
Goshia [24]

(2x² - 5) - (3x² + 4).

Pretend that there is a -1 in front of :(3x² + 4).

(2x^2-5)-1(3x^2+4)

2x^2-5-3x^-4

2x^2-3x^2-5-4

=-x^2-9

Answer: -x^2-9

3 0
3 years ago
Point b has coordinates (-8,15) and lies on the circle whose equation is x^2+y^2=289. If an angles is drawn in standard position
Alenkinab [10]

Answer:

\cos \theta=-\dfrac{8}{17}

Step-by-step explanation:

Coordinates of Point b=(-8,15)

b lies on the circle whose equation is x^2+y^2=289

x^2+y^2=17^2

Comparing with the general form a circle with center at the origin: x^2+y^2=r^2

The radius of the circle =17 which is the length of the hypotenuse of the terminal ray through point b.

For an angle drawn in standard position through point b,

x=-8 which is negative

y=15 which is positive

Therefore, the angle is in Quadrant II.

\cos \theta=\dfrac{Adjacent}{Hypotenuse} \\$Adjacent=-8\\Hypotenuse=17\\\cos \theta=\dfrac{-8}{17} \\\cos \theta=-\dfrac{8}{17}

8 0
2 years ago
Help on these precalc problems 14-20
Nadya [2.5K]
15) factor out cos: cos(x)(sin(x)+1)=0
Now this is true when either cos(x)=0 (x=pi/2 and 3pi/2)
Or when sin(x)=-1 (x=3pi/2)
So it's solutions are pi/2 and 3pi/2
7 0
2 years ago
A university's freshman class has 10000 students. 2500 of those students are majoring in Engineering. What percentage of the fre
Musya8 [376]

Answer:

25%

Step-by-step explanation:

2500*4 = 10000

10000/4 = 2500

its 1/4 of the students

25%

8 0
3 years ago
Read 2 more answers
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