Answer:
2
1/3
Step-by-step explanation:
A(xA, yA) = A (3,1)
B(xB,yB)=B(5,5)
the gradient=(yB-yA)/ (xB-xA)=(5-1)/(5-3)=4/2=2
C(4,7),D(10,9)
the gradient=(yD-yC)/(xD-xC)=(9-7)/(10-4)=2/6=1/3
(72/80)x90=81
Divide seventy-two by eight and multiply it Ninety.
<h3>
Answer:</h3>
- B. f(x) = 3,000(0.85)^x
- $1566.02
<h3>
Step-by-step explanation:</h3>
Part A
At the end of the year, the value of the computer system is ...
... (beginning value) - 15% · (beginning value) = (beginning value) · (1 - 0.15)
... = 0.85 · (beginning value)
Since the same is true for the next year and the next, the multiplier after x years will be 0.85^x. Then the value after x years is ...
... f(x) = (beginning value) · 0.85^x
The beginning value is given as $3000, so this is ...
... f(x) = 3000·0.85^x
____
Part B
For x=4, this is ...
... f(4) = 3000·0.85^4 = 3000·0.52200625 ≈ 1566.02
The value after 4 years is $1566.02.
