1.5r – 3r + 8r + 2.5r

Mathematics

1 answer:

Svetllana [295]2 years ago

5 0

Answer:

Step-by-step explanation:

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What is true for: y = 13(x - 4)2 - 4

notka56 [123]

Answer:

y=78

Step-by-step explanation:

y=13(x-4) 2-4

y=(13-52) -2

y=(-24+104)

y=78

7 0

3 years ago

Each week, Alfonso earns $85 for every shift he works at the theater and $15 for every dog-walking job. He uses the expression 8

sesenic [268]

So you didn't put an actual question. To find the money he makes you just plug in the numbers.
If he works 4 shifts at the theater you replace x with 4. Then, you find 85 x 4. You do the same thing with 15y.

8 0

3 years ago

A total of 50 juniors and seniors were given a mathematics test. The 35 juniors attained an average score of 80 while the 15 sen

Alik [6]

Answer:

Step-by-step explanation:

Firstly, we need to calculate the total score of the junior students and the total score of the senior students.

The total score of the junior students is 35 * 80 = 2,800

The total score of the senior students is 15 * 70 = 1050

The total score is thus 2,800 + 1,050 = 3,850

The average score of the 50 students is thus 3,850/50 which equals 77

8 0

3 years ago

the line y=2x-4 is dilated bt a scale factor of 3/2 and centered at the origin. Write an equation that represent that image of t

Veseljchak [2.6K]

Answer: $y = 2x -6$

Step-by-step explanation:

Since, If (x,y) represents the coordinates of a line, then after dilation about the origin by the scale factor k, the coordinates of the resultant line will get by the rule,

$(x,y)\rightarrow (kx,ky)$

Here, The equation of the given line is,

y = 2x - 4

x-intercept and y-intercept of the line are (2,0) and (0,-4) respectively,

Hence, the line y = 2x - 4 will be passes through the points (2,0) and (0,-4),

By the above property,

The dilated line about the origin will be passes through the points (3,0) and (0,-6), ( Because (3/2× 2, 3/2×0) = (3,0) and (3/2×0, 3/2×-4) = (0,-6) )

Hence, the equation of transformed line after dilation,

$y-0 = \frac{-6-0}{0-3}(x-3)$