All categories

2 years ago

1.5r – 3r + 8r + 2.5r

Mathematics

1 answer:

Svetllana [295]2 years ago

5 0

Answer:

Step-by-step explanation:

You might be interested in

Diagonals of an isosceles trapezoid are perpendicular to each other and the sum of the lengths of its bases is 2a. What is its

sergey [27]

Area= a*height
the formula for an isosceles trapezoid is 1/2(base1+base2)*height. 1/2 base 2 and 2a will simplify to a base length of a. a times height or a*height

7 0

3 years ago

Read 2 more answers

What is the momentum of 200kg portable if it travels 50 meters in 5seconds

kvasek [131]

Momentum = mass * velocity

50 meters in 5 seconds = 50/5 = 10 m / second

Required momentum = 200*10 = 2,000

I cant remember how to write the units for this.

5 0

2 years ago

I need help plz find m M

Firlakuza [10]

Answer:

60°

I think that answer

8 0

3 years ago

Find the number of terms and the degree of this polynomial -3p^8+2p^2-5

Hoochie [10]

Answer:

The degree if the polynomial is 8.

Step-by-step explanation:

When the polynomial is of the form ax^n+bx^(n-1)+.........+c, then n is the degree of the polynomial which in this case is 8.

as the given polynomial has three terms so it is trinomial.

3 0

3 years ago

the first group of students consists of 10 and their average age was 13 years old the next group consisted of 30 students and th

Kazeer [188]

Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : $\text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}$

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. $13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130$ (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. $9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270$ (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

Combined students of both groups (first and next group )= 10+30=40

Now , the average of both groups = $\dfrac{\text{Sum of combined students}}{\text{combined students}}$

$=\dfrac{400}{40}=10$

Hence, the average was 9 years old find the average age of both groups is 10 years old.

4 0

3 years ago

1.5r – 3r + 8r + 2.5r​

1.5r – 3r + 8r + 2.5r