Part 1: Do not reject H0. There has not been a significant change in the viewing audience proportions.(The above conclusion holds as the p-value is greater than the significance level of 0.05)
Part 2:
H0:
Ha:
Part 3: The test statistic is given as 3.0081.
Part 4: The p-value is given as 0.39037
Step-by-step explanation:
As per the data
Part 2
H0:
Ha:
Part 3
As per the sample is of 300 homes, the expected values are given as
ABC=p(ABC)*300=0.30*300=90
CBS=p(CBS)*300=0.27*300=81
NBC=p(NBC)*300=0.26*300=78
IND=p(IND)*300=0.17*300=51
Now the values actually are given as
ABC=94
CBS=71
NBC=88
IND=47
So the test static is given as
So the test statistic is given as 3.0081.
Part 4
Now the degree of freedoms are given as 4-1=3
and chi square is given as 3.0081 so for α = 0.05 , the p-value is given as 0.39037
Part 1.
As the value of p in part 4 is greater than the value of α = 0.05, thus Do not reject H0. There has not been a significant change in the viewing audience proportions.(The above conclusion holds as the p-value is greater than the significance level of 0.05)
