Answer:
The chosen option (considering enrollment costs and opportunity cost) is:
b) College course.
Explanation:
a) Data and Calculations:
Costs/Benefits
College Course Community Course
Cost $2,600 $1,390
Opportunity costs -2,080 2,080
Net costs $520 $3,470
Distance to course 0.40 miles 16 miles
(walking distance) (driving distance)
Timing of course Weekday Weekend
Number of meetings 16 8
b) With the College course option, you will earn $2,080 ($260 * 8) weekdays to offset part of the enrollment cost. With the Community course option, $2,080 will be lost in opportunity cost, thereby increasing the total costs incurred. These costs are apart from the driving costs associated with traveling 16 miles to the Community Course at the local library.
Well, since there's no options
Accounting : providing information regarding all financial aspects in the company
Marketing : determining kinds strategies to introduce company's products to the market
Management : Organizing all part of the company in order to reach company's goal
Answer:
Q = 450
P = 35
Explanation:
TR = P x Q = (75 - 0.1Q) x Q = -0.1Q2 + 75Q
Then, Cost = (30Q + 1,000)
Profit: Total revenue - C
-0.1q2 + 75Q - 30q - 1,000 = -0.1q2 + 45q - 1,000
as this is a quadratic function we identify a b c:
a= -0.1 b = 45 x = -1000
the profit maximum point is at the vertex:
-b/2a = -45/ 2(-0.1) = -45/-0.1 = 450
The profit maximize at Q = 450
P = 75 - 0.1x450 = 35
The value of car after three years is equal to the original price times the multiplier raised to a 3 (because of number of years). This is shown in the equation below,
V = P x (1 - r)^3
Substituting the given values,
V = ($15,000) x (1 - 0.2)^3
The value of the car after three years is equal to $7,680. The answer is letter D.