Given f(x)=3x+8 and g(x)=6x+6
then what is (f+g)(−1))?
1 answer:
<span>f(x)=3x+8 and g(x)=6x+6
(f + g)(x) = f(x) + g(x)
= </span>3x+8 + (6x + 6) = 3x + 6x + 8 + 6 = 9x + 14<span>
</span>(f + g)(x) = <span> 9x + 14
</span>
(f + g)(-1) = <span> 9*-1 + 14 = -9 + 14 = 5
</span>
<span>(f + g)(-1) = 5</span>
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Answer:
b+10g-x
Step-by-step explanation:
3x-4x=x
New equation becomes:
b+10g-x
1.99/32=0.06 an oz
3.69/64=0.05 an oz
5.85/96=0.06 an oz
therefore it is 64 oz
The slope of the tangent line to
at
is given by the derivative of
at that point:

Factorize the numerator:

We have
approaching -1; in particular, this means
, so that

Then

and the tangent line's equation is

Nope.........................................................