Answer:
5 units
Step-by-step explanation:
Let point O be the point of intersection of the kite diagonals.
|OF| = 2, |OH| = 5
|FH| = |OF| + |OH| = 2 + 5 = 7
FH and EG are the diagonals of the kite. Hence the area of thee kite is:
Area of kite EFGH = (FH * EG) / 2
Substituting:
35 = (7 * |EG|) / 2
|EG| * 7 = 70
|EG| = 10 units
The longer diagonal of a kite bisects the shorter one, therefore |GO| = |EO| = 10 / 2 = 5 units
x = |GO| = |EO| = 5 units
To solve this problem you must apply the proccedure shown below:
1. You have the following points given in the problem above:
A<span>(-2,3), B(9,3), C(5,6) and D(2,6)
2. When you plot them, you obtain the figure shown in the graph attached.
3. Therefore, as you can see,
the answer is: the figure is a trapezoid, which is define as a quadrilateral with two parallel sides.</span>
I think it would be a im not sure