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Hunter-Best [27]
3 years ago
12

A tank of water holding 528 kl of water begain to empty at a rate of 10 kl/min at the same time a another tank whitch is empty b

egins to fill at a rate of 14kl/min let k repreasens the number of kiloliters of water and let t repreasent time in min the system models the solution
How long will it take for each tank to have the Same amount of water , and how much water will that be

It will take __minitutes for both tanks to hold equal amounts of water . They will each hold ___ kiloliters.
Mathematics
1 answer:
torisob [31]3 years ago
8 0
This is a system of equations.  The first equation represents the tank being emptied and the second equation represents the tank being filled:

k = -10t + 528
k = 14t

To solve this system of equations, we will use substitution. The second equation says that k is equal to 14t, so we can substitute 14t for k in the first equation.

14t = -10t + 528
24t = 528
t = 22

Now that we have t, we can use it to find k by plugging it in to the second equation:

k = 14(22)
k = 308

So, it will take 22 minutes for both tanks to hold equal amounts of water. They will each hold 308 kiloliters.
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H(t) = -16t^2 +48t+72
Rama09 [41]

A function is a relationship between inputs and outputs, such that an input is mappable to one output only

The height of the rocket 1 second after launch is <u>104 feet</u>

The reason the height value above is correct is as follows

The given equation for the height of the rocket is presented as follows;

h(t) = -16·t² + 48·t + 72

Where;

h = The height of the rocket above ground in feet

t = The time in seconds

The given function gives the height of the rocket above ground in feet <em>t</em> seconds after the rocket is launched

Height of the rocket 1 seconds after launch is h(1) = -16×1² + 48×1 + 72 = 104

Therefore, the height of the rocket 1 second after launch, h(1) = <u>104 feet</u>

Learn more about functions here:

brainly.com/question/17095526

7 0
3 years ago
(a) the number 561 factors as 3 · 11 · 17. first use fermat's little theorem to prove that a561 ≡ a (mod 3), a561 ≡ a (mod 11),
Vitek1552 [10]
LFT says that for any prime modulus p and any integer n, we have

n^p\equiv n\pmod p

From this we immediately know that

a^{561}\equiv a^{3\times11\times17}\equiv\begin{cases}(a^{11\times17})^3\pmod3\\(a^{3\times17})^{11}\pmod{11}\\(a^{3\times11})^{17}\pmod{17}\end{cases}\equiv\begin{cases}a^{11\times17}\pmod3\\a^{3\times17}\pmod{11}\\a^{3\times11}\pmod{17}\end{cases}

Now we apply the Euclidean algorithm. Outlining one step at a time, we have in the first case 11\times17=187=62\times3+1, so

a^{11\times17}\equiv a^{62\times3+1}\equiv (a^{62})^3\times a\stackrel{\mathrm{LFT}}\equiv a^{62}\times a\equiv a^{63}\pmod3

Next, 63=21\times3, so

a^{63}\equiv a^{21\times3}=(a^{21})^3\stackrel{\mathrm{LFT}}\equiv a^{21}\pmod3

Next, 21=7\times3, so

a^{21}\equiv a^{7\times3}\equiv(a^7)^3\stackrel{\mathrm{LFT}}\equiv a^7\pmod3

Finally, 7=2\times3+1, so

a^7\equiv a^{2\times3+1}\equiv (a^2)^3\times a\stackrel{\mathrm{LFT}}\equiv a^2\times a\equiv a^3\stackrel{\mathrm{LFT}}\equiv a\pmod3

We do the same thing for the remaining two cases:

3\times17=51=4\times11+7\implies a^{51}\equiv a^{4+7}\equiv a\pmod{11}

3\times11=33=1\times17+16\implies a^{33}\equiv a^{1+16}\equiv a\pmod{17}

Now recall the Chinese remainder theorem, which says if x\equiv a\pmod n and x\equiv b\pmod m, with m,n relatively prime, then x\equiv b{m_n}^{-1}m+a{n_m}^{-1}n\pmod{mn}, where {m_n}^{-1} denotes m^{-1}\pmod n.

For this problem, the CRT is saying that, since a^{561}\equiv a\pmod3 and a^{561}\equiv a\pmod{11}, it follows that

a^{561}\equiv a\times{11_3}^{-1}\times11+a\times{3_{11}}^{-1}\times3\pmod{3\times11}
\implies a^{561}\equiv a\times2\times11+a\times4\times3\pmod{33}
\implies a^{561}\equiv 34a\equiv a\pmod{33}

And since a^{561}\equiv a\pmod{17}, we also have

a^{561}\equiv a\times{17_{33}}^{-1}\times17+a\times{33_{17}}^{-1}\times33\pmod{17\times33}
\implies a^{561}\equiv a\times2\times17+a\times16\times33\pmod{561}
\implies a^{561}\equiv562a\equiv a\pmod{561}
6 0
4 years ago
Sylvie finds the solution to the system of equations by graphing.
Softa [21]

Answer:

The correct answer is:

A coordinate grid with 2 lines. The first line passes through the points (negative 1.5, 0), (0, negative 1), and (3, negative 3). The second line passes through the points (negative 1.5, 0), (0, 1), and (3, 3).

Step-by-step explanation:

We are given the system of equations as:

1.\ y=-\dfrac{2}{3}x-1\\2.\ y=\dfrac{2}{3}x+1\\

<em>We have 2 equations here with variables x and y so we use coordinate grid with 2 lines having axis as x and y.</em>

<em></em>

As per the given options, <em>we can see that coordinate of one point has y = 0 and other point has x = 0.</em>

So, let us put y = 0 and x =0, in both the equations one by one and have a look at the value of x coordinate.

y = 0, Equation (1) becomes:

0=-\dfrac{2}{3}x-1\\\Rightarrow 1 =-\dfrac{2}{3}x\\\Rightarrow x = - 1.5

So, one coordinate is (-1.5, 0)

x = 0, Equation (1) becomes:

y=-\dfrac{2}{3}\times 0-1\\\Rightarrow y =-1

So, other coordinate is (0, -1)

And the point (3, -3) also satisfies the given equation.

y = 0, Equation (2) becomes:

0=\dfrac{2}{3}x+1\\\Rightarrow 1 =-\dfrac{2}{3}x\\\Rightarrow x = - 1.5

So, one coordinate is (-1.5, 0)

x = 0, Equation (2) becomes:

y=\dfrac{2}{3}\times 0+1\\\Rightarrow y =1

So, other coordinate is (0, 1)

And the point (3, 3) also satisfies the given equation.

Please refer to the <em>attached graph and points on lines</em>.

So, correct answer is:

A coordinate grid with 2 lines. The first line passes through the points (negative 1.5, 0), (0, negative 1), and (3, negative 3). The second line passes through the points (negative 1.5, 0), (0, 1), and (3, 3).

3 0
3 years ago
Read 2 more answers
Find t10 for the geometric sequence.<br> Please help!
Ksivusya [100]

Answer:

Step-by-step explanation:

Common ratio r = 2

t₁₀ = t₁r⁹ = -2×2⁹ = -2¹⁰ = -1024

6 0
3 years ago
Rasheed need to save $235. To earn money, he plans to wash cars and charge $12 for each. Enter two estimates Rasheed could use t
Murrr4er [49]
 the awnser is 240+10=24

6 0
3 years ago
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