A=1/2h(b1+b2) solve for b2. How on earth do I do this?
1 answer:
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Answer:
Step-by-step explanation:
1) Statements Reasons
ABCD is a trapezoid Given
AD ║ BC bases of trapezoid are parallel
∠AED = ∠CEB vertically opposite angles are equal
∠EBC = ∠ADE alternate interior angles are equal and BD is transversal
∠ECB = ∠EAD alternate interior angles are equal and AC is transversal
ΔAED ~ ΔCEB ∠ECB = ∠EAD & ∠AED = ∠BEC & ∠EBC = ∠ADE
all angles are same and their shape is same, so similar
2) hope you can write 2nd one as above two column proof
T is the mid point of QR
U is the mid point of QS
V is the mid point of RS
Definition: The segment of line joining the middle points of two sides of a triangle is called middle segment.
Inference: A middle segment of a triangle is parallel to the third side and its lengths is half the third side's.
so here TU ║ RV and TU = RV
UV ║ TR and UV = TR
so TUVR becomes a parallelogram
∠TUV = ∠TRV --------> condition 1
same goes with parallelogram TQUV
∠TQU = ∠UVT ----------> condition 2
same goes with parallelogram TUSV
∠UTV = ∠USV ------------> condition 3
from the above 3 conditions we can say
ΔQRS ~ ΔVUT
3) see the below figure for graph
in both triangles ∠B is common
AC and TS are parallel lines
BC and BA are transversals
∠C ∠S are equal --> corresponding angles
∠A ∠T are equal ---> corresponding angles
so ΔABC & ΔTBS are similar
