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3 years ago

True or false when you move a circle vertically the number that is part of the X term changes

Mathematics

2 answers:

zhenek [66]3 years ago

8 0

The answer on APEX is false.

matrenka [14]3 years ago

3 0

The correct answer is false

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PLS HELP ILL GIVE BRAINLEIST HELP PLSSSSS HURRRRRRYYYY

Monica [59]

Answer:

Are you asking for the pattern?

Step-by-step explanation:

If yes, then -

1st one = -2

2nd one = -3

3rd one = -4

4th one = -5

So, in each step in which we are moving forward, - 1 is being added to the equation

Please mark me as brainliest

6 0

3 years ago

Given f(x) = 4(x - 8), determine the value of f(10).

Komok [63]

Answer:

f(x) = 4(x - 8)

4 (10 -8) = 8

Step-by-step explanation:

6 0

4 years ago

Read 2 more answers

Can anybody explain to me what this question mean so it says "8 more than a number n is written ___________ in algebraic form"

Umnica [9.8K]

Answer:

They want you to put it into an expression so that it could be expressed. So, 8 more than n would be 8+n.

Hope This Helps!!! :D

3 0

3 years ago

Read 2 more answers

Steve is 15 years older than his sister michelle. in 8 years, he will be twice as old as michelle. how old is each of them now

Vinvika [58]

Let, the Age of Michelle = x
Age of Steve = x + 15

After 8 years, (x + 15 + 8) = 2(x + 8)
x + 23 = 2x + 16
2x - x = 23 - 16
x = 7
So, x + 15 = 22

In short, Age of Michelle is 7 & Age of Steve is 22 Years

Hope this helps!

6 0

3 years ago

Use the quadratic formula to solve x^2 -3x - 5 = 0. Round to two decimal places.

Evgen [1.6K]

Answer:

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=\frac{3+\sqrt{29}}{2},\:x=\frac{3-\sqrt{29}}{2}$

Step-by-step explanation:

Given the equation

$x^2\:-3x\:-\:5\:=\:0$

solving with the quadratic formula

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=1,\:b=-3,\:c=-5$

$x_{1,\:2}=\frac{-\left(-3\right)\pm \sqrt{\left(-3\right)^2-4\cdot \:1\cdot \left(-5\right)}}{2\cdot \:1}$

$x_{1,\:2}=\frac{-\left(-3\right)\pm \sqrt{29}}{2\cdot \:1}$

separating the solutions

$x_1=\frac{-\left(-3\right)+\sqrt{29}}{2\cdot \:1},\:x_2=\frac{-\left(-3\right)-\sqrt{29}}{2\cdot \:1}$

solving

$x=\frac{-\left(-3\right)+\sqrt{29}}{2\cdot \:\:1}$

$=\frac{3+\sqrt{29}}{2\cdot \:1}$

$=\frac{3+\sqrt{29}}{2}$

also solving

$\:x=\frac{-\left(-3\right)-\sqrt{29}}{2\cdot \:\:1}$

$=\frac{3-\sqrt{29}}{2\cdot \:1}$

$=\frac{3-\sqrt{29}}{2}$

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=\frac{3+\sqrt{29}}{2},\:x=\frac{3-\sqrt{29}}{2}$

7 0

3 years ago