3 years ago

Answer with solution

2 answers:

6 0

In general, the scalar multiple of k times u, is this:

 $k\vec u = k(ux, uy)=(Kux,Kuy)$

So, here's how we find $3\vec v$

$3\vec v = 3 * (2,4) = (3*2,3*4) 

= (6,12)$

The answer is (6,12).

denis-greek [22]3 years ago

5 0

6,12 the other person already explained it

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