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3 years ago

Answer with solution

2 answers:

6 0

In general, the scalar multiple of k times u, is this:

 $k\vec u = k(ux, uy)=(Kux,Kuy)$

So, here's how we find $3\vec v$

$3\vec v = 3 * (2,4) = (3*2,3*4) 

= (6,12)$

The answer is (6,12).

denis-greek [22]3 years ago

5 0

6,12 the other person already explained it

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Suppose you have a bag containing 15 red beads, 12 white beads and 8 black beads. You are going to draw one bead out of the bag.

iren [92.7K]

Answer:

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Step-by-step explanation:

Given a bag containing 15 red beads, 12 white beads and 8 black beads

n(S) = 15 + 12 +8 = 35

Let 'E1 be the event of selecting black beads and E2 be the event of selecting white beads

n(E1) = 8 and n(E2) = 12

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Probability of draw a white bead P( E2 ) = $\frac{n(E_{2} )}{n(S)}$

$P(E_{2}) = \frac{12}{35}$

probability that you draw a black bead or a white bead that is P(E1 U E2)

and E1 n E2 = ∅ (disjoint events)

Axiom of union

$P(E_{1}UE_{2} ) = P(E_{1})+P(E_{2}) - P(E_{1}nE_{2})\\$

E1 n E2 = ∅ ⇒ P(E1 n E2) = p(∅) = 0

$P(E_{1}UE_{2} ) = P(E_{1})+P(E_{2}) - 0$

$P(E_{1}UE_{2} ) = \frac{8}{35} +\frac{12}{35}$

$P(E_{1}UE_{2} ) = \frac{20}{35}$

$P(E_{1}UE_{2} ) = 0.571$

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Answer:

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