Answer:
If the equation is 3^x=n (it isnt showing up properly)
Part A: any number greater than 1 will work. Say 2.
Part B: any number less than or equal to 1.
Step-by-step explanation:
If you set x=2, 3^2=9 9>3
If you set x=0, 3^0=1 1<3
Answer:
where 
is the amount of banners sold.
Step-by-step explanation:
We know the team has already spent $40, and they earn #3.5 per banner.
Hence, with representing the amount of banners sold, the equation is
Answer:
The correct option is D) (5x − 2)(2x − 3).
Step-by-step explanation:
Consider the provided expression.
Where x is time in minutes.
We need to find the appropriate form of the expression that would reveal the time in minutes when the trough is empty.
When the trough is empty the whole expression becomes equal to 0.
Substitute the whole expression equal to 0 and solve for x that will gives us the required expression.
Now consider the provided option.
By comparison the required expression is D) (5x − 2)(2x − 3).
Hence, the correct option is D) (5x − 2)(2x − 3).
Answer:
Market price $400
Cost price $300
Step-by-step explanation:
MP: market price
CP: cost price
1. (MP x 0.9) - CP = 60
CP = 0.9MP - 60
2. MP - CP = 100
CP = MP - 100
0.9MP - 60 = MP - 100
MP - 0.9MP = 100 - 60
0.1MP = 40
MP = 400
Cost price = MP - 100 = 400 - 100 = 300
For this case, what we are going to do is use the following property:
Multiply an equation by a scalar.
In this case, the scalar will be:
k = -2
We have then that equation 2 will be:
k * (4x + y) = k * 1
-2 * (4x + y) = - 2 * 1
-8x-2y = -2
Answer:
The property that justifies this manipulation is:
Multiply an equation by a scalar.
