The equation of the perpendicular bisector of BC with B(-2, 1), and C(4, 2) is y = 7.6 - 6•x
<h3>Which method can be used to find the equation of the perpendicular bisector?</h3>
The slope, <em>m</em>, of the line BC is calculated as follows;
- m = (2 - 1)/(4 - (-2)) = 1/6
The slope of the perpendicular line to BC is -1/(1/6) = -6
The midpoint of the line BC is found as follows;
The perpendicular bisector is the perpendicular line constructed from the midpoint of BC.
The equation of the perpendicular bisector in point and slope form is therefore;
(y - 1.5) = -6•(x - 1)
y - 1.6 = -6•x + 6
y = -6•x + 6 + 1.6 = 7.6 - 6•x
Which gives;
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The answer is c, b/c...
20+(4/3)x=2x
-(4/3)x -(4/3)x
20=(2/3)x
20/(2/3)=(2/3)x/(2/3)
A: 30=x
First, we need to find the base. To do so, we will need to use the Pythagorean Theorem on one of the smaller triangles to solve for its unknown side. Then, we can double the base of the one to find the base of the whole.
Pythagorean Theorem: a^2 + b^2 = c^2
(12)^2 + b^2 = (16)^2
144 + b^2 = 256
b^2 = 112
b = 
b = 
total base = 2 x = 
Second, we can find the area. The formula for the area of a triangle is A = 1/2 x base x height.
A = 1/2 x x 12
A = x 12
A = 
units^2
Third, we can find the perimeter. The perimeter is the sum of all of the exterior sides.
P = 16 + 16 +
P = 32 + units
Hope this helps!! :)
Answer:
<h2>
aₙ = 7n - 10</h2>
Step-by-step explanation:
The nth term: 
So:
a₄ = a₁ + 3d
18 = a₁ + 3d ⇒ 3d = 18 - a₁
a₇ = a₁ + 6d
39 = a₁ + 6d
39 = a₁ + 2(18 - a₁)
39 = a₁ + 36 - 2a₁
39 = 36 - a₁
a₁ = -3
3d = 18 - (-3)
3d = 21
d = 7
So the nth term:
I don’t see a picture of the problem
