Let be the smaller integer. The larger integer is then
, and we have
We omit , since
is negative.
Then for we find
, but this is not odd.
There are no consecutive odd integers that satisfy the given condition!
A random survey of 9th and 12th grade students was taken regarding the type of drink they liked to order at their local coffee s
hop. The results are in the table below.
Specialty hot drink Specialty cold drink Totals
_______________________________________________________
9th graders 90 210 300
_______________________________________________________
12th graders 313 137 450
_______________________________________________________
Totals 403 347 750
_______________________________________________________
The percentage of voters in the survey who answered that they are both 12th graders and like to order specialty cold drinks is p%. What is the value of p rounded to the nearest percent?
A.) 39%
B.) 42%
C.) 65%
D.) 18%
Specialty hot drink Specialty cold drink Totals
_______________________________________________________
9th graders 90 210 300
_______________________________________________________
12th graders 313 137 450
_______________________________________________________
Totals 403 347 750
_______________________________________________________
The percentage of voters in the survey who answered that they are both 12th graders and like to order specialty cold drinks is p%. What is the value of p rounded to the nearest percent?
A.) 39%
B.) 42%
C.) 65%
D.) 18%
1 answer:
The table is shown below in the attached picture.
The grand total is the bottom rightmost cell, yellow in color.
12th graders AND likes specialty cold drinks is the cell colored green.
These 137 people are p% of the total. To get the value of p, we will divide this number (137) by grand total (750) and multiply by 100 to get the value.
%.
Rounded to the nearest percent, it is 18%. Answer choice D is correct.
ANSWER: D
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Answer:
<u>Perimeter</u>:
= 58 m (approximate)
= 58.2066 or 58.21 m (exact)
<u>Area:</u>
= 208 m² (approximate)
= 210.0006 or 210 m² (exact)
Step-by-step explanation:
Given the following dimensions of a rectangle:
length (L) = meters
width (W) = meters
The formula for solving the perimeter of a rectangle is:
P = 2(L + W) or 2L + 2W
The formula for solving the area of a rectangle is:
A = L × W
<h2>Approximate Forms:</h2>In order to determine the approximate perimeter, we must determine the perfect square that is close to the given dimensions.
13² = 169
14² = 196
15² = 225
16² = 256
Among the perfect squares provided, 16² = 256 is close to 252 (inside the given radical for the length), and 13² = 169 (inside the given radical for the width). We can use these values to approximate the perimeter and the area of the rectangle.
P = 2(L + W)
P = 2(13 + 16)
P = 58 m (approximate)
A = L × W
A = 13 × 16
A = 208 m² (approximate)
<h2>Exact Forms:</h2>
L = meters = 15.8745 meters
W = meters = 13.2288 meters
P = 2(L + W)
P = 2(15.8745 + 13.2288)
P = 2(29.1033)
P = 58.2066 or 58.21 m
A = L × W
A = 15.8745 × 13.2288
A = 210.0006 or 210 m²