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3 years ago

I took a picture of my math questions, here take a look.

Mathematics

1 answer:

PtichkaEL [24]3 years ago

7 0

Which one do you want to be awnserd

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In AGHI, the measure of ZI=90°, HI = 5.6 feet, and IG = 2.8 feet. Find the measure

lesantik [10]

Answer:

63.4

Step-by-step explanation:

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3 years ago

3a + 10 − 4q + 7a − 4q − 6.

soldi70 [24.7K]

Answer:

Step-by-step explanation:

3a+10-4q+7a-4q-6 combine terms

10a-8q+4

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3 years ago

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Can someone tell me how to write a linear equation from a graph?

kotykmax [81]

Answer:

y=mx+b

Step-by-step explanation:

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3 years ago

I don't even know where to start on this problem?

velikii [3]

I think you have to count 85 and go down like 85 86 87so the answer is 15

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3 years ago

For every 15 minutes of a show, there are two minutes to commercial. At this rate, if leila has seen 45 minutes of a show, how m

Ainat [17]

Answer:

51 minutes.

Step-by-step explanation:

We have been given that for every 15 minutes of a show, there are two minutes to commercial. At this rate, Leila has seen 45 minutes of a show. We are asked to find the time for which Leila has been watching TV.

We will use proportions to solve our given problem.

$\frac{\text{Minutes of TV show + Advertisement}}{\text{Minutes of TV show}}=\frac{15+2}{15}$

$\frac{\text{Minutes of TV show + Advertisement}}{\text{Minutes of TV show}}=\frac{17}{15}$

Upon substituting our given values, we will get:

$\frac{\text{Minutes of TV show + Advertisement}}{45}=\frac{17}{15}$

$\frac{\text{Minutes of TV show + Advertisement}}{45}\times 45=\frac{17}{15}\times 45$

$\text{Minutes of TV show + Advertisement}=\frac{17}{1}\times 3$

$\text{Minutes of TV show + Advertisement}=51$

Therefore, Leila has been watching TV together for 51 minutes.

8 0

3 years ago