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s344n2d4d5 [400]
2 years ago
14

Suppose a city with a population of 800,000 has been growing at a rate of ​3% per year. If this rate​ continues, find the popula

tion of this city in 24 years.
Mathematics
1 answer:
rusak2 [61]2 years ago
5 0

Answer:

57600000

Step-by-step explanation:

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If K is the midpoint of JL, JK = 8x+11 and KL = 14x-1, find JL.
gladu [14]

Step-by-step explanation:

Since, K is the midpoint of JL.

\therefore \: JK = KL \\ 8x + 11 = 14x - 1 \\ 11 + 1 = 14x - 8x \\ 12 = 6x \\  \frac{12}{6}  = x \\ 2 = x \\  \\  \because \: JL = JK + KL \\   \therefore \: JL = 8x + 11 + 14x - 1 \\ \therefore \: JL = 8x + 14x + 11 - 1 \\ \therefore \: JL = 22x + 10\\  \therefore \: JL = 22 \times 2 + 10..(plug \: x = 2) \\  \therefore \:JL = 44 + 10 \\  \huge \red{ \boxed{\therefore \:JL = 54}}

7 0
3 years ago
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1.Is the expression x3•x3•x3 equivalent to x3•3•3? Why or why not? Explain your reasoning.
Aleonysh [2.5K]
No because x3•x3•x3= 27x³ and x3•3•3=27x
7 0
3 years ago
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Find the distance between the two numbers on a number line. Write your answer as a decimal.
dangina [55]

Answer:

-0.574

Step-by-step explanation:

Subtract the two numbers to get the solution

7 0
3 years ago
0.1 is a rational number because it can be written as
Gnesinka [82]

Answer:

because it can be written in the <u>form</u><u> </u>of p/q

Where p and q are integers, and q is <u>not</u> equal to zero.

8 0
2 years ago
A manufacturer produces bolts of a fabric with a fixed width. A quantity q of this fabric (measured in yards) that is sold is a
BigorU [14]

Answer:

R'(20) = 2000

Step-by-step explanation:

We are given the following in the question:

Quantity, q

Selling price in dollars per yard, p

q=f(p)

Total revenue earned =

R(p)=pf(p)

f(20)=13000

This means that 13000 yards of fabric is sold when the selling price is 20 dollars per yard.

f′(20)=−550

This means that increasing the selling price by 1 dollar per yards there is a decrease in fabric sales by 550.

We have to find R'(20)

Differentiating the above expression, we have,

R'(p) = \displaystyle\frac{d(R(p))}{dp} = \frac{d(pf(p))}{dp} = f(p) + pf'(p)

Putting the values, we get,

R'(p) = f(p) + pf'(p)\\\\R'(20) = f(20) + 20(f'(20))\\\\R'(20) = 13000 + 20(-550) = 2000

7 0
3 years ago
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