Question

A rugby player passes the ball 7.88 m across the field, where it is caught at the same height as it left his hand. (Assume the player is facing the +x direction.) (a) At what angle (in degrees counterclockwise from the +x-axis) was the ball thrown if its initial speed was 13.1 m/s, assuming that the smaller of the two possible angles was used? ° counterclockwise from the +x-axis (b) What other angle (in degrees counterclockwise from the +x-axis) gives the same range? ° counterclockwise from the +x-axis

Answer 1

Explanation:

Given

Range of ball =7.88 m

Initial speed=13.1 m/s

and we know

Range of Projectile is

$R=\frac{u^2sin2\theta }{g}$

$13.1=\frac{13.1^2\times sin2\theta }{9.8}$

$7.88\times 9.8=13.1^2\times sin2\theta$

$sin2\theta =0.4499$

$2\theta =26.74^{\circ}$

$\theta =13.37 ^{\circ}$

(b)other angle would be complementary of $\theta$

$=90-\theta =76.63 ^{\circ}$