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frosja888 [35]
3 years ago
13

A projectile is fired with a velocity of 320 ms at an angle of 30 degree to a horizontal.1 Find the time to reach the maximum he

ight. 2 it's horizontal range.​
Physics
1 answer:
dedylja [7]3 years ago
6 0

(a) The time taken for the projectile to reach the maximum height is 32.65 s.

(b) The horizontal range of the projectile is 9,049.1 m.

The given parameters:

  • Initial velocity of the projectile, u = 320 m/s
  • Angle of projection, = 30 degrees

The time taken for the projectile to reach the maximum height is calculated as follows;

v_f = u- gt\\\\0 = 320 - 9.8t\\\\9.8t = 320\\\\t = \frac{320}{9.8} \\\\t = 32.65 \ s

The horizontal range of the projectile is calculated as follows;

R = \frac{u^2 sin(2\theta)}{g} \\\\R = \frac{320^2 \times sin(2\times 30)}{9.8} \\\\R = 9,049.1 \ m

Learn more about horizontal range here: brainly.com/question/12870645

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