Question

A projectile is fired with a velocity of 320 ms at an angle of 30 degree to a horizontal.1 Find the time to reach the maximum height. 2 it's horizontal range.​

Answer 1

(a) The time taken for the projectile to reach the maximum height is 32.65 s.

(b) The horizontal range of the projectile is 9,049.1 m.

The given parameters:

• Initial velocity of the projectile, u = 320 m/s
• Angle of projection, = 30 degrees

The time taken for the projectile to reach the maximum height is calculated as follows;

$v_f = u- gt\\\\0 = 320 - 9.8t\\\\9.8t = 320\\\\t = \frac{320}{9.8} \\\\t = 32.65 \ s$

The horizontal range of the projectile is calculated as follows;

$R = \frac{u^2 sin(2\theta)}{g} \\\\R = \frac{320^2 \times sin(2\times 30)}{9.8} \\\\R = 9,049.1 \ m$

Learn more about horizontal range here: brainly.com/question/12870645