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Archy [21]
3 years ago
9

Marking brainliest help pls the formula are there to help ^

Physics
1 answer:
natta225 [31]3 years ago
6 0

Answer:

Explanation:

Look at the equation for Potential Energy. PE = mass times gravity times the height. Filling in and solving for h:

34.3 = .5(9.8)h so

34.3 = 4.9h so

h = 7 meters

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A 87.0 kg astronaut is working on the engines of a spaceship that is drifting through space with a constant velocity. The astron
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Answer:

259.62521 seconds

Explanation:

m_1 = Mass of astronaut = 87 kg

m_2 = Mass of wrench = 0.57 kg

v_1 = Velocity of astronaut

v_2 = Velocity of wrench = 22.4 m/s

Here, the linear momentum is conserved

m_1v_1=m_2v_2\\\Rightarrow v_1=\frac{m_2v_2}{m_1}\\\Rightarrow v_1=\frac{0.57\times 22.4}{87}\\\Rightarrow v_1=0.14675\ m/s

Time = Distance / Speed

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The time taken to reach the ship is 259.62521 seconds

4 0
3 years ago
A mass of (200 g) of hot water at (75.0°C) is mixed with cold water of mass M at (5.0°C). The final temperature of the mixture i
SIZIF [17.4K]

The mass of the cold water, given the data from the question is 500 g

<h3>Data obtained from the question</h3>
  • Mass of warm water (Mᵥᵥ) = 200 g
  • Temperature warm water (Tᵥᵥ) = 75 °C
  • Temperature of cold water (T꜀) = 5 °C
  • Equilibrium temperature (Tₑ) = 25 °C
  • Specific heat capacity of the water = 4.184 J/gºC
  • Mass of cold water (M꜀) =?

<h3>How to determine the mass of the cold water </h3>

Heat loss = Heat gain

MᵥᵥC(Tᵥᵥ – Tₑ) = M꜀C(Tₑ – T꜀)

200 × 4.184 (75 – 25) = M꜀ × 4.184(25 – 5)

41840 = M꜀ × 83.68

Divide both side 83.68

M꜀ = 41840 / 83.68

M꜀ = 500 g

Learn more about heat transfer:

brainly.com/question/6363778

#SPJ1

4 0
2 years ago
If Tony and Tanya both run at the same speed and in the same direction and they both run for the same amount of time, what can y
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Answer: They travel equal distances

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- Also, both run for the same amount of time: let time = c

Therefore, distance covered by Tony and Tanya = speed x time taken

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8 0
3 years ago
(06.01 MC)
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Answer: C. Both observation 1 and observation 2

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