Answer:
0.087976 Nm
Explanation:
The magnetic torque (τ) on a current-carrying loop in a magnetic field is given by;
τ = NIAB sinθ --------- (i)
Where;
N = number of turns of the loop
I = current in the loop
A = area of each of the turns
B = magnetic field
θ = angle the loop makes with the magnetic field
<em>From the question;</em>
N = 200
I = 4.0A
B = 0.70T
θ = 30°
A = π d² / 4 [d = diameter of the coil = 2.0cm = 0.02m]
A = π x 0.02² / 4 = 0.0003142m² [taking π = 3.142]
<em>Substitute these values into equation (i) as follows;</em>
τ = 200 x 4.0 x 0.0003142 x 0.70 sin30°
τ = 200 x 4.0 x 0.0003142 x 0.70 x 0.5
τ = 200 x 4.0 x 0.0003142 x 0.70
τ = 0.087976 Nm
Therefore, the torque on the coil is 0.087976 Nm
Work done is given by product of force and displacement due to that force
So here we will have
here we know that
Now work done is given as
so it will do 16 J work to move the box
True.
Density = mass / volume, Unit = g / cm³.
This is a common unit because of its affiliation with the SI unit and because that also our popular liquid which is water = 1 g/cm³
Your weight will decrease ALOT from traveling there and living there if you were without shelter or a space suit you would immediately freeze to get tied up in the storm which is also called the "red dot of mars" or the "eye of mars" which is an ongoing storm.