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xeze [42]
3 years ago
5

Which is a valid velocity reading for an object?

Physics
2 answers:
kirill115 [55]3 years ago
6 0
I believe it’s 45 m/s, correct me if wrong
natita [175]3 years ago
4 0
The answer is B. You cannot have 0 velocity. If you don’t include direction, then it is only considered speed.
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A concave lens can only form a. A. real image. B. reversed image. C. virtual image. D. magnified image.
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A concave lens can only form a virtual image. The correct option among all the options that are given in the question is the third option or option "C". Concave lenses are mostly thinner in the middle compared to its edges. I hope that this answer has come to your help.
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The terminals of a diode are called the
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A diode has two terminals. The positive side is called the anode, and the negative one is called the cathode.

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A 0.110 kg cube of ice (frozen water) is floating in glycerine. The glycerine is in a tall cylinder that has inside radius 3.70
Sonbull [250]

Answer:

the distance by which the height of the  liquid in the cylinder change after the ice gets melted = 0.528 cm

Explanation:

The change in volume of glycerin when the ice cube is placed on the surface of the glycerin can be represented as:

V = \frac{m}{ \rho}

Given that ;

the mass of the ice cube (m) = 0.11 kg = 0.110 × 10³ g

density of the glycerine (\rho) = 1.260 kg/L = 1.260 g/cm³

Then:

V = \frac{0.110*10^3 \ g}{1.260 \ g/cm^3}

V = 0.0873*10^3 \ cm^3 (\frac{1L}{10^3 cm^3})

V = 0.0873 L

Now;Initially the volume of the glycerin before the ice cube starts to melt is:

V_1 = V_i + V\\\\V_1 = V_i+ 0.0873 \ L

However; the volume of the water produced by the 0.11 kg ice cube = 0.11*10^3 \ cm^3

The expression for change in the volume of glycerin after the ice cube starts to melt is as follows:

V_2 = V_i + V"

replacing V" with 0.11*10^3 \ cm^3 ; we have:

V_2 = V_i (0.11*10^3 \ cm^3 )(\frac{1 \ L }{10^3 \ cm^3})

V_2 = V_i + 0.11 \ L

The overall total change in the volume of the glycerin is illustrated as:

V_f = V_2 - V_1

Now; from the foregoing ; lets replace the respective value of V_2 and V_1 in the above equation ; we have;

V_f = (V_i + 0.11 \ L) - (V_i + \ 00873 \ L)\\ \\V_f = 0.11 L - 0.0873 \ L\\\\V_f = 0.0227 \ L

The formula usually known to be the volume of a cylinder is :

V = \pi r ^2 h

For the question ; we will have:

V_f = \pi r ^2 h

making h the subject of the  formula ; we have:

h = \frac{V_f}{\pi r^2}

replacing 0.0227 L for V_fand the given value of radius which is = 3.70 cm; we have:

h = \frac{0.0227 \ L ( \frac{10^3 \ cm^3}{1\ L})}{\pi * (3.70 cm)^2}

h = \frac{22.7 \ cm^3}{\pi * (3.70 cm)^2}\\\\h = 0.528 \ \ cm

Thus ; the distance by which the height of the  liquid in the cylinder change after the ice gets melted = 0.528 cm

8 0
4 years ago
a plane takes off at 34 m/s if it accelerates from rest and takes 7.2 seconds to lift off find the acceleration
skelet666 [1.2K]
See attachment for your Answer.

5 0
4 years ago
A ship anchored at sea is rocked by waves that have crests Lim apart the waves travel at 70m/S, at what frequency do the waves r
inessss [21]

Question: A ship anchored at sea is rocked by waves that have crests 100 m apart the waves travel at 70m/S, at what frequency do the waves reach the ship?

Answer:

0.7 Hz

Explanation:

Applying,

v = λf............... Equation 1

Where v = velocity of the wave, f = frequency fo the wave, λ = wavelength of the wave

make f the subject of the equation

f = v/λ................. Equation 2

From the question,

Given: v = 70 m/s, λ = 100 m ( distance between successive crest)

Substitute these values into equation 2

f = 70/100

f = 0.7 Hz

Hence the frequency at which the wave reach the ship is 0.7 Hz

3 0
3 years ago
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