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3 years ago

The highest common factor of 18, 24, 36 is

Mathematics

2 answers:

yawa3891 [41]3 years ago

6 0

If you list all the common factors, (1,2,3,6), you see the highest common factor is 6

ale4655 [162]3 years ago

3 0

The highest common factor of 18, 24, 36 is 6

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Without using logarithm tables, find the value of x given that: 2log2/3 = 1/2logx - log 18 + log 16

sweet-ann [11.9K]

Answer:

$x=\frac{1}{4}$

Step-by-step explanation:

Given:

$2log(\frac{2}{3})=\frac{1}{2}log(x)-log(18)+log(16)$

Use the Power Rule Law:

$log(\frac{2}{3}^2)=log(x^{1/2})+log(16)-log(18)$

Use the Quotient Rule Law:

$log(\frac{4}{9})=log(\sqrt{x})+log(\frac{16}{18})$

Use the Product Rule Law:

$log(\frac{4}{9})=log(\frac{16\sqrt{x}}{18})$

Simplify:

$log(\frac{4}{9})=log(\frac{8\sqrt{x}}{9})$

$\frac{4}{9}=\frac{8\sqrt{x}}{9}$

$4=8\sqrt{x}$

$\frac{4}{8}=\sqrt{x}$

$\frac{1}{2}=\sqrt{x}$

$\frac{1}{4}=x$

5 0

2 years ago

(x - 2)(x² + 2x + 4) = 0

Ber [7]

We have to find the value of x from the given equation.

(x - 2)(x² - 2x + 2) = 0 is a quadratic equation, so it will have two values.

Step: Write the equation in simplest form.

(x - 2)(x² - 2x + 1) = 0

Step: Solve the problem by spiltting method.

(x-2)(x² - x -x + 1) = 0
(x - 2)(x²-x - x + 1) = 0
(x - 2) [x(x - 1) -1(x -1)]
(x - 2)[(x-1)(x-1)]

Step: Solve the problem with using algebraic formula.

{x-1](x-1)

Step : We have used a²-b² to solve the problem.

(x-2)(x² - x -x + 1) = 0

(x - 2)(x²-x - x + 1) = 0

(x - 2) [x(x - 1) -1(x -1)]

(x - 2)[(x-1)(x-1)]

Therefore, the possible factorization is (x - 2)[(x-1)(x-1)].

4 0

3 years ago

Which of the following equations is paralllel to the line y+3x+1 and passes through the point (6,-3)

RideAnS [48]

Answer:

y=3x-21

Step-by-step explanation:

a line is parallel if the slopes of the lines are the same

so that means that out line should look something like this

y=3x+b

then, we use our point given to find b

-3=18+b

b=-21

the equation of out line is y=3x-21

7 0

3 years ago

The plate is rotated 90° about the origin in the counterclockwise direction. In the image trapezoid, what are the coordinates of

Jet001 [13]

Answer:

The coordinates of the endpoints of the side congruent to side EF is:

E'(-8,-4) and F'(-5,-7).

Step-by-step explanation:

" when point M (h, k) is rotated about the origin O through 90° in anticlockwise direction or we can say counter clockwise. The new position of point M (h, k) will become M' (-k, h) "

We are given a trapezoid such that the vertices of trapezoid are:

E(-4,8) , F(-7,5) , G(-4,3) , H(-2,5)

Then the new coordinates after the given transformation is:

E(-4,8) → E'(-8,-4)

F(-7,5) → F'(-5,-7)

G(-4,3) → G'(-3,-4)

H(-2,5) → H'(-5,-2)

Hence the coordinates of the endpoints of the side congruent to side EF is:

E'(-8,-4) and F'(-5,-7).

4 0

3 years ago

Helppp....................

zalisa [80]

Answer:

Step-by-step explanation:

.............................

6 0

3 years ago

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