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blondinia [14]
3 years ago
11

I don't understand this

Mathematics
1 answer:
Elanso [62]3 years ago
7 0

Answer:

d. 56,000

Step-by-step explanation:

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prohojiy [21]
A = 34 x 2 = 68
b = 56/2 = 28

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Triangle ABC has a perimeter of 22cm I WILL MARK YOU AS BRAINLIEST
Andreyy89

Answer:

Step-by-step explanation:

Number of vertices

3

Variable constraints

a>0 and b>0

Diagonal lengths

(data not available)

Height

b

Area

A = (a b)/2

Centroid

x^_ = (a/3, b/3)

Mechanical properties:

Area moment of inertia about the x-axis

J_x invisible comma x = (a b^3)/12

Area moment of inertia about the y-axis

J_y invisible comma y = (a^3 b)/12

Polar moment of inertia

J_zz = 1/12 a b (a^2 + b^2)

Product moment of inertia

J_x invisible comma y = -1/24 a^2 b^2

Radii of gyration about coordinate axes

r_x = b/sqrt(6)

r_y = a/sqrt(6)

Distance properties:

Side lengths

a | sqrt(a^2 + b^2) | b

Hypotenuse

sqrt(a^2 + b^2)

Perimeter

p = sqrt(a^2 + b^2) + a + b

Inradius

r = 1/2 (-sqrt(a^2 + b^2) + a + b)

Circumradius

R = 1/2 sqrt(a^2 + b^2)

Generalized diameter

sqrt(a^2 + b^2)

Convexity coefficient

χ = 1

Mean triangle area

A^_ = (a b)/24

7 0
3 years ago
If n and m are integers and n2+m2 is even, which of the following is impossible?
boyakko [2]


None of 

 these imposible hope this helps :)

6 0
3 years ago
A credit card company requires that its customers choose a 3 digit, numerical code to access their online account. Each digit sh
Citrus2011 [14]

Given :

A credit card company requires that its customers choose a 3 digit.

Each digit should be chosen from 0, 1, 2, 3, 4, 5, 6, 7, 8 or 9.

So there are 10 possibilities for each digit.

To Find :

How many different three digit codes are there.

Solution :

We know, possibility of choosing each digit is 10.

So, total number of three digit codes are :

T=10\times 10\times 10\\\\T=1000

Therefore, their are 1000 different three digit codes.

Hence, this is the required solution.

4 0
3 years ago
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