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german
4 years ago
10

Describe the steps to balancing a chemical equation.

Chemistry
1 answer:
scZoUnD [109]4 years ago
6 0
Identify each element found in the equation. The number of atoms of each type of atom must be the same on each side of the equation once it has been balanced.

What is the net charge on each side of the equation? The net charge must be the same on each side of the equation once it has been balanced.

If possible, start with an element found in one compound on each side of the equation. Change the coefficients (the numbers in front of the compound or molecule) so that the number of atoms of the element is the same on each side of the equation. Remember, to balance an equation, you change the coefficients, not the subscripts in the formulas.

Once you have balanced one element, do the same thing with another element. Proceed until all elements have been balanced. It's easiest to leave elements found in pure form for last.

Check your work to make certain the charge on both sides of the equation is also balanced.
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3 years ago
Within each ______ in the periodic table, elements have similar properties because they have the same number of valence electron
borishaifa [10]

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group

Explanation:

elements in the same group have the same number of valence electrons

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4 years ago
If an object has a temperature of 42 °C, to which of the following objects will it transfer heat?
koban [17]

Answer:

B

Explanation:

3 0
3 years ago
Solution. Identify the concentration of the nye
Lana71 [14]

Answer:

12.5%

Explanation:

Given data:

Volume/Volume % = ?

Volume of solute = 25 mL

Volume of solution = 200 mL

Solution:

Formula:

v/v% = ( volume of solute / volume of solution ) × 100

by putting values,

v/v% = ( 25 mL / 200 mL)  × 100

v/v% = 0.125  × 100

v/v% = 12.5%

3 0
3 years ago
2. Calculate the joules of energy required to heat 454.3g of water<br> frum 5.4°C to 98.6°C.
Tasya [4]

Answer:

176984.38J

Explanation:

E = mC∆T

Where E is the energy in joules

M is the mass of water

C is the specific heat capacity of water =4.184J/g°C

It is known that it will take 4.184J of energy to change the temperature of water by one degree Celsius.

∆T = 98.6°c - 5.4°c

= 93.2°c

∆H = 454.3g × 4.18J/g°C × 93.2°c

= 176984.3768

176984.38J

7 0
4 years ago
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