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Angelina_Jolie [31]
4 years ago
13

Within each ______ in the periodic table, elements have similar properties because they have the same number of valence electron

s.
Period
Row
Group
Metals

Plz this is really really really urgent
Chemistry
1 answer:
borishaifa [10]4 years ago
6 0

Answer:

group

Explanation:

elements in the same group have the same number of valence electrons

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The ΔHvap of a certain compound is 47.45 kJ·mol−1 and its ΔSvap is 59.15 J·mol−1·K−1. What is the boiling point of this compound
podryga [215]

Answer:

802.2 K

Explanation:

To solve this problem we can use the formula:

  • Tb = ΔHvap / ΔSvap

Where Tb is the boiling point (in K).

We already know the values of both ΔHvap and ΔSvap, so we calculate Tb:

  • ΔHvap = 47.45 kJ·mol⁻¹ = 47.45x10³J·mol⁻¹

Tb = 47.45x10³J·mol⁻¹/59.15 J·mol⁻¹·K⁻¹

  • Tb = 802.2 K

So the boiling point of the compound is 802.2 K (or 529 °C)

7 0
3 years ago
An insulated cup contains 66.0g of water at 22.00oC. A 28.50g sample of metal at 95.25oC is added. The final temperature of the
Vsevolod [243]

Answer:

Specific heat of metal of the metal is 0.8394J/g°C

Explanation:

The heat the water gain is the same losing for the metal. The equation is:

m(Metal)*ΔT(Metal)*S(Metal) = m(Water)*ΔT(Water)*S(Water)

<em>Where m is mass: 66.0g water and 28.5g Metal</em>

<em>ΔT is change in temperature: (95.25°C-27.84°C) = 67.41°C for the metal and (27.84°C - 22.00°C) = 5.84°C for the water</em>

<em>And S is specific heat of water (4.184J/g°C) and the metal</em>

<em />

Replacing:

28.5g*67.41°C*S(Metal) = 66.0g*5.84°C*4.184J/g°C

S(Metal) = 0.8394J/g°C

<h3>Specific heat of metal of the metal is 0.8394J/g°C</h3>

<em />

7 0
3 years ago
How does skin defend the body against pathogens?
stira [4]
C. Because skin acts like a barrier that doesn’t allow pathogens or other micro organisms to enter unless their is a cut, scratch, etc. on your skin.
7 0
3 years ago
If 45.0 liters of oxygen is measured at 24.0C, what would be its volume at standard temperature?
nika2105 [10]

The volume of the oxygen gas at standard temperature  is 41.36 liters.

The given parameters;

  • <em>initial volume of oxygen, V₁ = 45 L</em>
  • <em>temperature of oxygen, T₁ = 24 ⁰C = 297 K</em>
  • <em>standard temperature, T₂ = 0 ⁰C = 273 K</em>

<em />

The volume of the oxygen gas at standard temperature is determined by applying Charles law as shown below;

\frac{V_1}{T_1} = \frac{V_2}{T_2} \\\\V_2 = \frac{V_1 T_2}{T_1} \\\\V_2 = \frac{45 \times 273}{297} \\\\V_2 = 41.36 \ L

Thus, the volume of the oxygen gas at standard temperature  is 41.36 L.

Learn more here:brainly.com/question/16927784

6 0
3 years ago
1) Find the mass of 2.7 moles of NaCl.
sukhopar [10]

Answer:

157. 788 grams

Explanation:

number of moles = mass/molar mass.

hence the mass = molar mass × number of moles

m = 58.44 × 2.7 = 157.788 grams

5 0
2 years ago
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