Answer:
802.2 K
Explanation:
To solve this problem we can use the formula:
Where Tb is the boiling point (in K).
We already know the values of both ΔHvap and ΔSvap, so we calculate Tb:
- ΔHvap = 47.45 kJ·mol⁻¹ = 47.45x10³J·mol⁻¹
Tb = 47.45x10³J·mol⁻¹/59.15 J·mol⁻¹·K⁻¹
So the boiling point of the compound is 802.2 K (or 529 °C)
Answer:
Specific heat of metal of the metal is 0.8394J/g°C
Explanation:
The heat the water gain is the same losing for the metal. The equation is:
m(Metal)*ΔT(Metal)*S(Metal) = m(Water)*ΔT(Water)*S(Water)
<em>Where m is mass: 66.0g water and 28.5g Metal</em>
<em>ΔT is change in temperature: (95.25°C-27.84°C) = 67.41°C for the metal and (27.84°C - 22.00°C) = 5.84°C for the water</em>
<em>And S is specific heat of water (4.184J/g°C) and the metal</em>
<em />
Replacing:
28.5g*67.41°C*S(Metal) = 66.0g*5.84°C*4.184J/g°C
S(Metal) = 0.8394J/g°C
<h3>Specific heat of metal of the metal is 0.8394J/g°C</h3>
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C. Because skin acts like a barrier that doesn’t allow pathogens or other micro organisms to enter unless their is a cut, scratch, etc. on your skin.
The volume of the oxygen gas at standard temperature is 41.36 liters.
The given parameters;
- <em>initial volume of oxygen, V₁ = 45 L</em>
- <em>temperature of oxygen, T₁ = 24 ⁰C = 297 K</em>
- <em>standard temperature, T₂ = 0 ⁰C = 273 K</em>
<em />
The volume of the oxygen gas at standard temperature is determined by applying Charles law as shown below;

Thus, the volume of the oxygen gas at standard temperature is 41.36 L.
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Answer:
157. 788 grams
Explanation:
number of moles = mass/molar mass.
hence the mass = molar mass × number of moles
m = 58.44 × 2.7 = 157.788 grams