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3 years ago

What is the [H+] concentration of a solution with a pH of 3.78

Chemistry

1 answer:

lianna [129]3 years ago

6 0

Answer:

[H+] = 1.66 x $10^{-4}$

Explanation:

To find the [H+] concentration of a solution, we can use the formula:

$[H+] = 10^{-pH}$

Let's plug in the pH.

$[H+] = 10^{-3.78}$

Evaluate the exponent.

[H+] = 1.66 x $10^{-4}$

Hope this helps!

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stiv31 [10]

Answer:

C. It decreases by a factor of 4

Explanation:

F1 = kq1*q2/r²

F2 = kq1*q2/(2r)² = kq1*q2/(4r²) = kq1*q2/(r²*4) = F1/4

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2 years ago

Consider the following gas phase reaction:

snow_tiger [21]

Answer:

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now 400 ml of NO × 2 mol of NO2/2 mol of NO

= 400 ml of NO2

now 500 ml of O2 × 2 mol of NO2/1 mol of O2

= 1000 ml of NO2

now 400 ml of NO2 × 1 mol of O2/2 mol of NO

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2 years ago

What happens to the population growth in a logistic growth pattern as it approaches carrying capacity?

AveGali [126]

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2 years ago

Consider the reaction of peroxydisulfate ion (S2O2−8) with iodide ion (I−) in aqueous solution: S2O2−8(aq)+3I−(aq)→2SO2−4(aq)+I−

kolbaska11 [484]

Answer:

r = 3.61x $10^{-6}$ M/s

Explanation:

The rate of disappearance (r) is given by the multiplication of the concentrations of the reagents, each one raised of the coefficient of the reaction.

r = k. $[S2O2^{-8} ]^{x} x [I^{-} ]^{y}$

K is the constant of the reaction, and doesn't depends on the concentrations. First, let's find the coefficients x and y. Let's use the first and the second experiments, and lets divide 1º by 2º :

$\frac{r1}{r2} = \frac{0.018^{x} x0.036^{y} }{0.027^xx0.036^y}$