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kati45 [8]
4 years ago
11

2. Calculate the joules of energy required to heat 454.3g of water frum 5.4°C to 98.6°C.

Chemistry
1 answer:
Tasya [4]4 years ago
7 0

Answer:

176984.38J

Explanation:

E = mC∆T

Where E is the energy in joules

M is the mass of water

C is the specific heat capacity of water =4.184J/g°C

It is known that it will take 4.184J of energy to change the temperature of water by one degree Celsius.

∆T = 98.6°c - 5.4°c

= 93.2°c

∆H = 454.3g × 4.18J/g°C × 93.2°c

= 176984.3768

176984.38J

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4 0
3 years ago
What are the coefficients that balance the following chemical equation? ___Ag + ___ S → ___Ag2S
Andrej [43]

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3 0
3 years ago
Read 2 more answers
What mass of FeSO4^2- x 6H20 (Molar Mass=260g/mol) is required to produce 500 mL of a .10M iron (II) sulfate solution.
lukranit [14]

Answer:

The correct option is: B. 13g

Explanation:

Given: Molar mass of iron (II) sulfate: m = 260g/mol,

Molarity of iron (II) sulfate solution: M =  0.1 M,

Volume of iron (II) sulfate solution: V = 500 mL = 500 × 10⁻³ = 0.5 L           (∵ 1L = 1000mL)

Mass of iron (II) sulfate taken: w = ? g

<em>Molarity</em>: M = \frac{n}{V (L)} = \frac{w}{m\times V(L)}

Here, n- total number of moles of solute, w - given mass of solute, m- molar mass of solute, V- total volume of solution in L

∴ <em>Molarity of iron (II) sulfate solution:</em>  M = \frac{w}{m\times V(L)}

⇒  w = M\times m\times V(L)

⇒  w = (0.1 M)\times (260g/mol)\times (0.5L)

⇒  <em>mass of iron (II) sulfate taken:</em> w = 13 g

<u>Therefore, the mass of iron (II) sulfate taken for preparing the given solution is 13 g.</u>

5 0
3 years ago
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