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Fofino [41]
3 years ago
6

How many solutions dose the equation 5x + 3x -4 =10 A.0 B.1 C.2 D. Indefinitely many

Mathematics
1 answer:
Gnesinka [82]3 years ago
3 0

Answer:

The answer is 14/8

Step-by-step explanation:

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A clinical test on humans of a new drug is normally done in three phases. Phase I is conducted with a relatively small number of
navik [9.2K]

Answer:

A clinical test on humans of a new drug is normally done in three phases. Phase I is conducted with a relatively small number of healthy volunteers. For​ example, a phase I test of a specific drug involved only 7 subjects.

Step-by-step explanation:

6 0
2 years ago
Consider the function ƒ(x) = x2. Which of the following functions shifts ƒ(x) downward 5 units and to the right 3 units?
Sunny_sXe [5.5K]
The answer is 12.6 that’s the answer right there
5 0
2 years ago
What is reasonable first step that can be used to solve the equation 2(x+6)=3(x-4)+5?
blagie [28]

Answer:

Distribute 2 to (x + 6) and 3 to (x-4)

Step-by-step explanation:

8 0
2 years ago
Please answer this in two minutes
Sunny_sXe [5.5K]

Answer:

D. 1800°

Step-by-step explanation:

The given polygon has 12 sides.

The formula for finding the sum of the interior angles of an n-sided polygon is given as, ( n − 2 ) × 180.

Where n is the number of sides of the polygon.

Thus, the sum of the interior angles of the 12 sided polygon given above is:

(12 - 2) × 180

= 10 × 180 = 1800°

<em>Sum of the measures of the interior angles of the 12-sided polygon is D. 1800°</em>

4 0
3 years ago
What is the interquartile range (IQR) of the following data set 17 16 21 15 25 22 18 23 17
Pepsi [2]

IQR = 6

First locate the median Q_{2} at the centre of the data arranged in ascending order. Then locate the lower and upper quartiles Q_{1} and Q_{3} located at the centre of the data to the left and right of the median.

Note that if any of the above are not whole values then they are the average of the values either side of the centre.

rearrange data in ascending order

15 16 ↓17 17 18 21 22 ↓23 25

                     ↑

Q_{2} = 18

Q_{1} = \frac{16+17}{2} = 16.5

Q_{3} = \frac{22+23}{2} = 22.5

IQR = Q_{3} - Q_{1} = 22.5 - 16.5 = 6




4 0
2 years ago
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