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trasher [3.6K]
3 years ago
9

HELP DUE TODAY

Mathematics
1 answer:
Fudgin [204]3 years ago
6 0
I think it is D
Hope my answer help you?
You might be interested in
Will anyone help me
Arada [10]

7/10, division is not possible so we right 0. ( zero point ) and multiply 7 by 10

(7*10)/10=70/10... 10 goes into 70, 7 times, so we write 0.7 (zero point seven)


1. 7/10 = 0.7, not repeating

4 20/30 = 2/3 = 0.666... repeating

13. 1/17/20 = 37/20 = 1.85

8 0
3 years ago
Read 2 more answers
Sabrina rode on a Ferris wheel at the state fair. The radius of the Ferris wheel was 143 feet. What is the approximate distance
ASHA 777 [7]
The awnser is C. 898.04 ft  To find the distance that Sabrina traveled you need to find the circumference of the circle by multiplying 3.14 time 143.  After that you multiply that product by 2 to get the circumference of the circle
The awnser you get is 898.04 ft
I hope this was helpful!
8 0
3 years ago
Solve the equation x−62=7
mel-nik [20]

Answer:

x = 69

hope this helped you

8 0
3 years ago
Read 2 more answers
90 POINTSSSSSSS:
denis23 [38]

Answer:

Part A:  12 plus x, the x being how much money he made on Sunday.

Part B: 2 plus x times 2

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Suppose you have 5 riders and 5 horses, and you want to pair them off so that every rider is assigned one horse (and no horse is
maw [93]

There are 120 ways in which 5  riders and 5 horses can be arranged.

We have,

5 riders and 5 horses,

Now,

We know that,

Now,

Using the arrangement formula of Permutation,

i.e.

The total number of ways ^nN_r = \frac{n!}{(n-r)!},

So,

For n = 5,

And,

r = 5

As we have,

n = r,

So,

Now,

Using the above-mentioned formula of arrangement,

i.e.

The total number of ways ^nN_r = \frac{n!}{(n-r)!},

Now,

Substituting values,

We get,

^5N_5 = \frac{5!}{(5-5)!}

We get,

The total number of ways of arrangement = 5! = 5 × 4 × 3 × 2 × 1 = 120,

So,

There are 120 ways to arrange horses for riders.

Hence we can say that there are 120 ways in which 5  riders and 5 horses can be arranged.

Learn more about arrangements here

brainly.com/question/15032503

#SPJ4

7 0
2 years ago
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