Solve for x.<br> Graph the solution.<br> 4x + 2 < 3x

The accompanying specific gravity values describe various wood types used in construction. 0.32 0.35 0.36 0.36 0.37 0.38 0.40 0.

Tems11 [23]

Answer:

Follows are the responses to the given question:

Step-by-step explanation:

Please find the complete question in the attached file.

$Stem\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Leaf\\\\$

$3\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 3\\\\3 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 5,6,6,7,8\\\\4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0,0,0,1,1,2,2,2,2,2,3,4\\\\4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 5,6,6,7,8,8,8\\\\5 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1,4,4\\\\$

$5 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 5,8\\\\6\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1\\\\6 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 6,6,7,8\\\\7 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ NONE\\\\7 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 6\\$

The stem & leaf show demonstrates that 0.55 for both the data is indeed a reasonable value.

The probable outlier is the data value 0.76.

The variability of the techniques is relatively large.

It show isn't symmetrical and seems to be optimistic.

6 0

3 years ago

a jet bomber traveling 500 mph arrived over its Target at the same time as its fighter jet escorted which left the same fate 2.5

vlada-n [284]

Since the jet bomber arrived over its Target at the same time as its fighter jet escorted, it took the jet bomber 0.34 h to reach the target.

<h3 />

To find the number of hours, we need to solve simultaneous equations.

<h3>What are simultaneous equations?</h3>

Simultaneous equations are pair of equations which contain two unknowns.

<h3>How to calculate the number of hours the bomber jet took off?</h3>

Let

D = distance travelled by both bomber jet and fighter jet.
t = time bomber jet took off
v = speed of bomber jet.
T = time fighter jet took off and
V = speed of fighter jet.

So, D = vt

D = 500t (1)

Also, D = VT

D = 60T (2)

Since jet bomber traveling 500 mph arrived over its Target at the same time as its fighter jet escorted which left the same fate 2.5 hours after the bomb took off.

T = t + 2.5

So, D = 60(t + 2.5) (3)

<h3>The required simultaneous equations</h3>

D = 500t (1)

D = 60(t + 2.5) (3)

Equating equations (1) and (3), we have

500t = 60(t + 2.5)

500t = 60t + 150

500t - 60t = 150

440t = 150

t = 150/440

t = 15/44

t = 0.34 h

So, it took the jet bomber 0.34 hours to reach the target.

Learn more about simultaneous equations here:

brainly.com/question/27829171

#SPJ1

8 0

2 years ago

Find the center and radius of the circle whose diameter has an endpoint at (-3, -4) and the origin.

Zina [86]

Given end points of diameter,

(x1,y1)=(-3,-4)

(x2,y2)=(0,0)

Now,

the equation of circle is,

(x-x1)(x-x2)+(y-y1)(y-y2)=0

or, (x+3)(x-0)+(y+4)(y-0)=0

or, x^2 +3x +y^2 +4y =0

or, x^2 +y^2 +3x + 4y=0

which is in the form of x^2 +y^2 +2gx +2fy + c=0

where,

g=3/2

h=2

c=0

Now,

$radius(r) = \sqrt{ {g}^{2} + {f}^{2} - c } \\ = \sqrt{ \frac{ {3}^{2} }{ {2}^{2} } + {2}^{2} - 0 } \\ = \sqrt{ \frac{9}{4} + 4} \\ = \sqrt{ \frac{25}{4} } \\ = \frac{5}{2}$

6 0

3 years ago

If I save 100 dollars every two weeks for a month how much will i have

lyudmila [28]

Answer:

200

Step-by-step explanation:

it also depends on how many weeks there are in the month but yeah 200 is right.

4 0

3 years ago

Solve, then check albebraically and graphically 7x+14=56

Cerrena [4.2K]

Answer:

7×+14=56

= 7×=56 -14

= × = 6

Step-by-step explanation:

I hope it helps you

7 0

3 years ago

Solve for x. Graph the solution. 4x + 2 < 3x - 3